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The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]?
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The order of stability of the following tautomeric compond is--: CH2=C...
The order of stability of the tautomeric compounds can be determined by analyzing the resonance structures and the stability of the resulting molecules. Let's analyze each compound in detail:
Compound 1: CH2=COH--CH2--C=O--CH3
- In this compound, the keto form is more stable. The double bond between carbon and oxygen is in conjugation with the carbonyl group, leading to resonance stabilization.
- The enol form, which has a double bond between carbon and oxygen, is less stable due to the lack of resonance stabilization.
Compound 2: CH3--C=O--CH2--C=--CH3
- In this compound, both the keto and enol forms are possible. However, the enol form is more stable due to the presence of a conjugated system.
- The double bond between the two carbons is in conjugation with the carbonyl group, leading to resonance stabilization and increased stability.
Compound 3: CH3--COH=CH--C=O--CH3
- In this compound, the enol form is more stable. The double bond between carbon and oxygen is in conjugation with the carbonyl group, leading to resonance stabilization.
- The keto form is less stable due to the lack of resonance stabilization.
Order of stability: 2 > 3 > 1
Explanation:
- Compound 2 is the most stable due to the presence of a conjugated system. The resonance stabilization provided by the conjugation of the double bond with the carbonyl group increases the stability of the molecule.
- Compound 3 is less stable than compound 2 but more stable than compound 1. The enol form of compound 3 has resonance stabilization due to the conjugation of the double bond with the carbonyl group.
- Compound 1 is the least stable among the three compounds. The keto form of compound 1 has some resonance stabilization due to the conjugation of the double bond with the carbonyl group, but it is not as stable as the enol forms of compounds 2 and 3.
In summary, the order of stability of the tautomeric compounds is as follows: 2 > 3 > 1. Compound 2 is the most stable due to the presence of a conjugated system, while compound 1 is the least stable.
Compound 1: CH2=COH--CH2--C=O--CH3
- In this compound, the keto form is more stable. The double bond between carbon and oxygen is in conjugation with the carbonyl group, leading to resonance stabilization.
- The enol form, which has a double bond between carbon and oxygen, is less stable due to the lack of resonance stabilization.
Compound 2: CH3--C=O--CH2--C=--CH3
- In this compound, both the keto and enol forms are possible. However, the enol form is more stable due to the presence of a conjugated system.
- The double bond between the two carbons is in conjugation with the carbonyl group, leading to resonance stabilization and increased stability.
Compound 3: CH3--COH=CH--C=O--CH3
- In this compound, the enol form is more stable. The double bond between carbon and oxygen is in conjugation with the carbonyl group, leading to resonance stabilization.
- The keto form is less stable due to the lack of resonance stabilization.
Order of stability: 2 > 3 > 1
Explanation:
- Compound 2 is the most stable due to the presence of a conjugated system. The resonance stabilization provided by the conjugation of the double bond with the carbonyl group increases the stability of the molecule.
- Compound 3 is less stable than compound 2 but more stable than compound 1. The enol form of compound 3 has resonance stabilization due to the conjugation of the double bond with the carbonyl group.
- Compound 1 is the least stable among the three compounds. The keto form of compound 1 has some resonance stabilization due to the conjugation of the double bond with the carbonyl group, but it is not as stable as the enol forms of compounds 2 and 3.
In summary, the order of stability of the tautomeric compounds is as follows: 2 > 3 > 1. Compound 2 is the most stable due to the presence of a conjugated system, while compound 1 is the least stable.
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The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]?
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The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]?.
The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The order of stability of the following tautomeric compond is--: CH2=COH--CH2--C=O--CH3--->[1] CH3--C=O--CH2--C=--CH3--->[2] CH3--COH=CH--C=O--CH3 [3]?.
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