8 men and 12 boys can finish a piece of work in 10 days while 6 men an...
Solution:
Step 1: Set up Equations
Let the time taken by one man alone to finish the work be "m" and the time taken by one boy alone to finish the work be "b".
We can set up the following two equations based on the given information:
1. 8m + 12b = 1/10 (the work done by 8 men and 12 boys in 10 days)
2. 6m + 8b = 1/14 (the work done by 6 men and 8 boys in 14 days)
Step 2: Solve the Equations
We can solve the above two equations simultaneously to find the values of "m" and "b".
Multiplying the first equation by 7 and the second equation by 5, we get:
1. 56m + 84b = 7/10
2. 30m + 40b = 1/14
Now, we can use any method to solve these two equations. Here, we will use the elimination method.
Multiplying the second equation by 21, we get:
3. 630m + 840b = 3/14
Subtracting equation 1 from equation 3, we get:
4. 574m + 756b = 1/35
Multiplying equation 2 by 3, we get:
5. 18m + 24b = 3/42
Subtracting equation 5 from equation 4, we get:
6. 556m + 732b = 1/35 - 3/42
Simplifying, we get:
6. 556m + 732b = 1/210
Multiplying equation 2 by 7, we get:
7. 42m + 56b = 1/2
Subtracting equation 7 from equation 1, we get:
8. 14m + 28b = 1/10 - 1/2
Simplifying, we get:
8. 14m + 28b = -2/5
Multiplying equation 8 by 3, we get:
9. 42m + 84b = -6/5
Adding equation 9 to equation 6, we get:
10. 598m + 816b = -1/210
Multiplying equation 2 by 5, we get:
11. 30m + 40b = 5/70
Subtracting equation 11 from equation 7, we get:
12. 12m + 16b = 1/2 - 5/70
Simplifying, we get:
12. 12m + 16b = 3/7
Multiplying equation 12 by 3, we get:
13. 36m + 48b = 9/7
Subtracting equation 13 from equation 10, we get:
14. 562m + 768b = -16/210
Simplifying, we get:
14. 281m + 384b = -8/105
Multiplying equation 12 by 14, we get:
15.