If all phone beta are the zeros of the polynomial f of its is equal to...
Given:
Polynomial f(x) = x^2 - 4x + 3
The zeros of the polynomial are the values of x for which f(x) = 0.
To Find:
The value of (α^2 * β^4 * m^2)
Solution:
To find the value of (α^2 * β^4 * m^2), we first need to find the values of α and β.
Finding the Zeros of the Polynomial:
To find the zeros of the polynomial f(x) = x^2 - 4x + 3, we set f(x) = 0 and solve for x.
x^2 - 4x + 3 = 0
Factoring the Polynomial:
The given quadratic equation does not factorize easily, so we can use the quadratic formula to find the zeros.
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, a = 1, b = -4, and c = 3.
Using the quadratic formula, we can find the values of x.
x = (-(-4) ± √((-4)^2 - 4(1)(3))) / (2(1))
x = (4 ± √(16 - 12)) / 2
x = (4 ± √4) / 2
x = (4 ± 2) / 2
Solving for x:
We have two possible solutions for x:
x1 = (4 + 2) / 2 = 6 / 2 = 3
x2 = (4 - 2) / 2 = 2 / 2 = 1
Therefore, the zeros of the polynomial f(x) = x^2 - 4x + 3 are x = 3 and x = 1.
Finding the Value of (α^2 * β^4 * m^2):
Now that we have found the values of α and β, we can substitute them into the expression (α^2 * β^4 * m^2) to find its value.
Let's assume that α = 3, β = 1, and m = 2.
(α^2 * β^4 * m^2) = (3^2 * 1^4 * 2^2)
= (9 * 1 * 4)
= 36
Therefore, the value of (α^2 * β^4 * m^2) is 36.
Answer:
The value of (α^2 * β^4 * m^2) is 36.
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