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Two cars started from the same point and traveled on a straight course in opposite directions for exactly 3 hours, at which time they were 300 miles apart. If one car traveled, on average, 10 miles per hour faster than the other car, what was the average speed of the slower car for the 3-hour trip?
  • a)
    40 miles per hour
  • b)
    45 miles per hour
  • c)
    50 miles per hour
  • d)
    55 miles per hour
  • e)
    60 miles per hour
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Two cars started from the same point and traveled on a straight course...
Let's denote the average speed of the slower car as x miles per hour. Since the faster car traveled, on average, 10 miles per hour faster than the slower car, the average speed of the faster car can be represented as (x + 10) miles per hour.
The total distance covered by the slower car in 3 hours is 3x miles, and the total distance covered by the faster car in 3 hours is 3(x + 10) miles.
Since they started from the same point and traveled in opposite directions, the total distance between them after 3 hours is the sum of the distances covered by both cars:
3x + 3(x + 10) = 300
Simplifying the equation:
3x + 3x + 30 = 300 6x + 30 = 300 6x = 300 - 30 6x = 270 x = 270 / 6 x = 45
Therefore, the average speed of the slower car for the 3-hour trip is 45 miles per hour.
The correct answer is (B) 45 miles per hour.
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