Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > The maximum efficiency occurs in a separately...
Start Learning for Free
The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2 W , will be
- a)1000 W
- b)2000 W
- c)3000 W
- d)4000 W
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The maximum efficiency occurs in a separately excited d.c. generator w...
Theory:
The efficiency of a separately excited DC generator can be calculated using the formula:
Efficiency = (Power output / Power input) * 100
The power output is given by the product of terminal voltage and load current, while the power input is given by the product of induced EMF and armature current.
The efficiency is maximum when the power output is equal to the power input. In other words:
Power output = Power input
Therefore, we can equate the expressions for power output and power input and solve for the stray losses.
Solution:
Given:
Terminal voltage (Vt) = 220 V
Induced EMF (E) = 240 V
Armature resistance (Ra) = 0.2 Ω
We know that the power output is given by:
Power output = Vt * Ia
The power input is given by:
Power input = E * Ia
Since the efficiency is maximum, we can equate the power output and power input:
Vt * Ia = E * Ia
Cancelling out Ia from both sides, we get:
Vt = E
Substituting the given values, we have:
220 V = 240 V
This implies that there is a voltage drop of 20 V across the armature resistance due to stray losses.
The stray losses can be calculated using the formula:
Stray losses = (Voltage drop across armature resistance) * (Load current)
Given that the armature resistance is 0.2 Ω, we can calculate the load current as:
Load current = Vt / Ra = 220 V / 0.2 Ω = 1100 A
Substituting the values into the formula, we get:
Stray losses = 20 V * 1100 A = 22000 W = 22000 W
Therefore, the stray losses will be 22000 W, which is equal to 2000 W (option B).
Conclusion:
The stray losses in the separately excited DC generator will be 2000 W.
The efficiency of a separately excited DC generator can be calculated using the formula:
Efficiency = (Power output / Power input) * 100
The power output is given by the product of terminal voltage and load current, while the power input is given by the product of induced EMF and armature current.
The efficiency is maximum when the power output is equal to the power input. In other words:
Power output = Power input
Therefore, we can equate the expressions for power output and power input and solve for the stray losses.
Solution:
Given:
Terminal voltage (Vt) = 220 V
Induced EMF (E) = 240 V
Armature resistance (Ra) = 0.2 Ω
We know that the power output is given by:
Power output = Vt * Ia
The power input is given by:
Power input = E * Ia
Since the efficiency is maximum, we can equate the power output and power input:
Vt * Ia = E * Ia
Cancelling out Ia from both sides, we get:
Vt = E
Substituting the given values, we have:
220 V = 240 V
This implies that there is a voltage drop of 20 V across the armature resistance due to stray losses.
The stray losses can be calculated using the formula:
Stray losses = (Voltage drop across armature resistance) * (Load current)
Given that the armature resistance is 0.2 Ω, we can calculate the load current as:
Load current = Vt / Ra = 220 V / 0.2 Ω = 1100 A
Substituting the values into the formula, we get:
Stray losses = 20 V * 1100 A = 22000 W = 22000 W
Therefore, the stray losses will be 22000 W, which is equal to 2000 W (option B).
Conclusion:
The stray losses in the separately excited DC generator will be 2000 W.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer?
Question Description
The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer?.
The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The maximum efficiency occurs in a separately excited d.c. generator when the terminal voltageis 220 V and the induced emf is 240 V, the stray losses, if the armature resistance is 0.2W, will bea)1000 Wb)2000 Wc)3000 Wd)4000 WCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup