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An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images?
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An object of 5cm height is placed at a distance of 20cm from the optic...
Given:
Height of object (h) = 5 cm
Distance of object from lens (u) = -20 cm (Negative sign indicates that the object is placed on the same side as the incident light)
Focal length of concave lens (f) = -18 cm (Negative sign indicates a concave lens)
To find:
1) Image distance (v)
2) Magnification (m)
Formula used:
The lens formula is given by:
1/f = 1/v - 1/u
The magnification (m) is given by:
m = -v/u
Calculation:
1) Image distance (v):
Using the lens formula,
1/f = 1/v - 1/u
Substituting the given values,
1/-18 = 1/v - 1/-20
Simplifying the equation,
1/-18 = (20 - v)/20
Cross-multiplying,
-18(20 - v) = -20
Expanding the equation,
-360 + 18v = -20
Rearranging the equation,
18v = -20 + 360
18v = 340
Dividing by 18,
v = 340/18
v ≈ 18.89 cm
The image distance is approximately 18.89 cm.
2) Magnification (m):
Using the magnification formula,
m = -v/u
Substituting the given values,
m = -18.89/(-20)
Simplifying the equation,
m = 0.9445
The magnification is approximately 0.9445.
Comparison between concave and convex lenses:
When a concave lens forms a virtual image, the magnification is always less than 1, indicating that the image is smaller than the object. In this case, the magnification is 0.9445.
On the other hand, when a convex lens forms a virtual image, the magnification can be greater than 1, indicating that the image is larger than the object. This occurs when the object is placed between the focal point and the lens. The magnification of a convex lens can vary depending on the position of the object.
Therefore, in the case of virtual images formed by both concave and convex lenses, the magnification can be different. The concave lens generally produces smaller virtual images, while the convex lens can produce both larger and smaller virtual images depending on the object's position relative to the lens.
Height of object (h) = 5 cm
Distance of object from lens (u) = -20 cm (Negative sign indicates that the object is placed on the same side as the incident light)
Focal length of concave lens (f) = -18 cm (Negative sign indicates a concave lens)
To find:
1) Image distance (v)
2) Magnification (m)
Formula used:
The lens formula is given by:
1/f = 1/v - 1/u
The magnification (m) is given by:
m = -v/u
Calculation:
1) Image distance (v):
Using the lens formula,
1/f = 1/v - 1/u
Substituting the given values,
1/-18 = 1/v - 1/-20
Simplifying the equation,
1/-18 = (20 - v)/20
Cross-multiplying,
-18(20 - v) = -20
Expanding the equation,
-360 + 18v = -20
Rearranging the equation,
18v = -20 + 360
18v = 340
Dividing by 18,
v = 340/18
v ≈ 18.89 cm
The image distance is approximately 18.89 cm.
2) Magnification (m):
Using the magnification formula,
m = -v/u
Substituting the given values,
m = -18.89/(-20)
Simplifying the equation,
m = 0.9445
The magnification is approximately 0.9445.
Comparison between concave and convex lenses:
When a concave lens forms a virtual image, the magnification is always less than 1, indicating that the image is smaller than the object. In this case, the magnification is 0.9445.
On the other hand, when a convex lens forms a virtual image, the magnification can be greater than 1, indicating that the image is larger than the object. This occurs when the object is placed between the focal point and the lens. The magnification of a convex lens can vary depending on the position of the object.
Therefore, in the case of virtual images formed by both concave and convex lenses, the magnification can be different. The concave lens generally produces smaller virtual images, while the convex lens can produce both larger and smaller virtual images depending on the object's position relative to the lens.
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An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images?
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An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images?.
An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object of 5cm height is placed at a distance of 20cm from the optical centre of a concave lens of focal length 18cm. Calculate (1) image distance and (2) the magnification in this case. ii). Compare the values of magnification obtained by a concave lens and a convex lens when when both the lenses form virtual images?.
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