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What are the hybridization and shapes of the following molecules?
(i) CH3F
(ii) HC ≡ N
(i) CH3F
(ii) HC ≡ N
- a)(i) sp2, trigonal planar; (ii) sp3, tetrahedral
- b)(i) sp3, tetrahedral; (ii) sp, linear
- c)(i) sp, linear; (ii) sp2, trigonal planar
- d)(i) sp2, trigonal planar, (ii) sp2, trigonal planar
Correct answer is option 'B'. Can you explain this answer?
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What are the hybridization and shapes of the following molecules?(i) C...
CH3F - sp3 hybridised carbon, tetrahedral shape
(ii) HC = N - sp hybridised carbon, linear shape.
(ii) HC = N - sp hybridised carbon, linear shape.
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What are the hybridization and shapes of the following molecules?(i) C...
(i) CH3F:
The central atom in CH3F is carbon (C).
Hybridization:
Carbon is sp3 hybridized in CH3F. This is because carbon forms four sigma bonds. One sigma bond is formed with each of the three hydrogen atoms (H), and one sigma bond is formed with the fluorine atom (F).
Shape:
The shape of CH3F is tetrahedral. This is because carbon has four regions of electron density (three sigma bonds and one lone pair of electrons), resulting in a tetrahedral arrangement of these regions.
(ii) HC:
The central atom in HC is carbon (C).
Hybridization:
Carbon is sp hybridized in HC. This is because carbon forms one sigma bond with hydrogen (H) and one sigma bond with chlorine (Cl).
Shape:
The shape of HC is linear. This is because carbon has two regions of electron density (one sigma bond with hydrogen and one sigma bond with chlorine), resulting in a linear arrangement of these regions.
The central atom in CH3F is carbon (C).
Hybridization:
Carbon is sp3 hybridized in CH3F. This is because carbon forms four sigma bonds. One sigma bond is formed with each of the three hydrogen atoms (H), and one sigma bond is formed with the fluorine atom (F).
Shape:
The shape of CH3F is tetrahedral. This is because carbon has four regions of electron density (three sigma bonds and one lone pair of electrons), resulting in a tetrahedral arrangement of these regions.
(ii) HC:
The central atom in HC is carbon (C).
Hybridization:
Carbon is sp hybridized in HC. This is because carbon forms one sigma bond with hydrogen (H) and one sigma bond with chlorine (Cl).
Shape:
The shape of HC is linear. This is because carbon has two regions of electron density (one sigma bond with hydrogen and one sigma bond with chlorine), resulting in a linear arrangement of these regions.
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What are the hybridization and shapes of the following molecules?(i) CH3F(ii) HC ≡ Na)(i) sp2, trigonal planar; (ii) sp3, tetrahedralb)(i) sp3, tetrahedral; (ii) sp, linearc)(i) sp, linear; (ii) sp2, trigonal planard)(i) sp2, trigonal planar, (ii) sp2, trigonal planarCorrect answer is option 'B'. Can you explain this answer?
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What are the hybridization and shapes of the following molecules?(i) CH3F(ii) HC ≡ Na)(i) sp2, trigonal planar; (ii) sp3, tetrahedralb)(i) sp3, tetrahedral; (ii) sp, linearc)(i) sp, linear; (ii) sp2, trigonal planard)(i) sp2, trigonal planar, (ii) sp2, trigonal planarCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What are the hybridization and shapes of the following molecules?(i) CH3F(ii) HC ≡ Na)(i) sp2, trigonal planar; (ii) sp3, tetrahedralb)(i) sp3, tetrahedral; (ii) sp, linearc)(i) sp, linear; (ii) sp2, trigonal planard)(i) sp2, trigonal planar, (ii) sp2, trigonal planarCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What are the hybridization and shapes of the following molecules?(i) CH3F(ii) HC ≡ Na)(i) sp2, trigonal planar; (ii) sp3, tetrahedralb)(i) sp3, tetrahedral; (ii) sp, linearc)(i) sp, linear; (ii) sp2, trigonal planard)(i) sp2, trigonal planar, (ii) sp2, trigonal planarCorrect answer is option 'B'. Can you explain this answer?.
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