First divide 4052 and 12576
12576=4052 X 3 + 420
then divide 4052 and 420
4025= 420 X 9 + 272
then divide 420 and 272
420 = 272 X 1 +148
then divide 272 and 148
272= 148 X 1 +124
then divide 148 and 124
148= 124 X 1+ 24
then divide 124 and 24
124= 24X 5 +4
then divide 24 and 4
24 =4 X 6 + 0

therefore HCF = 4
Hope it will help

Euclid's Division Algorithm to Find HCF of 4052 and 12576

Euclid's Division Algorithm is a method used to find the highest common factor (HCF) of two given numbers. It involves repeatedly dividing the larger number by the smaller number until the remainder becomes zero. The HCF is the last non-zero remainder obtained in this process.

Let's apply Euclid's Division Algorithm to find the HCF of 4052 and 12576.

Step 1: Divide the larger number by the smaller number
In this case, 12576 is larger than 4052. So, we divide 12576 by 4052.

12576 ÷ 4052 = 3 remainder 3420

Step 2: Divide the previous divisor by the remainder
Now, we divide 4052 by the remainder obtained in the previous step, which is 3420.

4052 ÷ 3420 = 1 remainder 632

Step 3: Repeat the process until the remainder becomes zero
Next, we divide 3420 by 632.

3420 ÷ 632 = 5 remainder 60

Continuing the process, we divide 632 by 60.

632 ÷ 60 = 10 remainder 32

Finally, we divide 60 by 32.

60 ÷ 32 = 1 remainder 28

Step 4: HCF is the last non-zero remainder
Since the remainder 28 is non-zero, it is the highest common factor (HCF) of 4052 and 12576.

Therefore, the HCF of 4052 and 12576 is 28.

Summary:
Applying Euclid's Division Algorithm, we divided the larger number (12576) by the smaller number (4052) and obtained a remainder of 3420. Then, we continued dividing the previous divisor by the remainder until the remainder became zero. The last non-zero remainder, 28, is the HCF of 4052 and 12576.