Heat generated while transferring 96000 coulomb of charge in two hours through a potential difference 40V

To calculate the heat generated during the transfer of charge, we can use the formula:

Heat (H) = Voltage (V) * Charge (Q)

Given:
Charge (Q) = 96000 coulomb
Voltage (V) = 40V
Time (t) = 2 hours

Converting time from hours to seconds
1 hour = 3600 seconds
2 hours = 2 * 3600 = 7200 seconds

Calculating the heat generated
H = V * Q
H = 40V * 96000 coulomb
H = 3840000 Joules

Therefore, the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of 40V is 3840000 Joules.

Explanation:
When an electric current flows through a conductor, heat is generated due to the resistance offered by the conductor. This heat is a result of the conversion of electrical energy into thermal energy.

In this case, a charge of 96000 coulomb is transferred through a potential difference of 40V. The potential difference (V) represents the amount of electrical energy per unit charge. The charge (Q) represents the amount of charge transferred.

The formula to calculate the heat generated (H) is given by H = V * Q. By substituting the given values, we can calculate the heat generated.

The time taken for the transfer of charge is also given as 2 hours. Since the formula for heat does not involve time, it is not directly used in the calculation of heat. However, it is important to note the time taken as it affects the overall power dissipated (P = H / t) during the transfer.

In conclusion, the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of 40V is 3840000 Joules. This heat is a result of the resistance offered by the conductor and the conversion of electrical energy into thermal energy.