Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A three-phase 33 kV, oil-circuit breaker is r...
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A three-phase 33 kV, oil-circuit breaker is rated 1500 A, 2000 MVA, 2 s. The symmetrical breaking current for this breaker would be
- a)40 kA
- b)25 kA
- c)35 kA
- d)50 kA
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A three-phase 33 kV, oil-circuit breaker is rated 1500 A, 2000 MVA, 2 ...
Given Data:
- Voltage rating of the circuit breaker (V) = 33 kV
- Current rating of the circuit breaker (I) = 1500 A
- Power rating of the circuit breaker (S) = 2000 MVA
- Time duration for the circuit breaker to interrupt the fault current (t) = 2 s
Formula Used:
- Symmetrical breaking current (Ibk) = S / (√3 * V)
Calculation:
- The formula to calculate the symmetrical breaking current is Ibk = S / (√3 * V)
- Plugging in the given values, we get Ibk = 2000 MVA / (√3 * 33 kV)
Simplifying the Calculation:
- Converting the power rating from MVA to kVA, we get 2000 MVA = 2000 * 1000 kVA = 2,000,000 kVA
- Substituting the values, Ibk = 2,000,000 kVA / (√3 * 33 kV)
- Simplifying further, Ibk = 2,000,000 / (√3 * 33) kA
Calculating the Symmetrical Breaking Current:
- Evaluating the expression, we get Ibk ≈ 35 kA
Conclusion:
- The symmetrical breaking current for this three-phase 33 kV oil-circuit breaker is approximately 35 kA. Hence, option 'C' is the correct answer.
- Voltage rating of the circuit breaker (V) = 33 kV
- Current rating of the circuit breaker (I) = 1500 A
- Power rating of the circuit breaker (S) = 2000 MVA
- Time duration for the circuit breaker to interrupt the fault current (t) = 2 s
Formula Used:
- Symmetrical breaking current (Ibk) = S / (√3 * V)
Calculation:
- The formula to calculate the symmetrical breaking current is Ibk = S / (√3 * V)
- Plugging in the given values, we get Ibk = 2000 MVA / (√3 * 33 kV)
Simplifying the Calculation:
- Converting the power rating from MVA to kVA, we get 2000 MVA = 2000 * 1000 kVA = 2,000,000 kVA
- Substituting the values, Ibk = 2,000,000 kVA / (√3 * 33 kV)
- Simplifying further, Ibk = 2,000,000 / (√3 * 33) kA
Calculating the Symmetrical Breaking Current:
- Evaluating the expression, we get Ibk ≈ 35 kA
Conclusion:
- The symmetrical breaking current for this three-phase 33 kV oil-circuit breaker is approximately 35 kA. Hence, option 'C' is the correct answer.
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Community Answer
A three-phase 33 kV, oil-circuit breaker is rated 1500 A, 2000 MVA, 2 ...
Concept:
Breaking current: It expresses the highest number of short-circuit currents that the breakers are capable of breaking under specified conditions of transient recovery voltage and power frequency voltage. It is expressed in kA (RMS) at contact separation. The breaking capacities are divided into two types.
- Symmetrical breaking capacity of a circuit breaker
- Asymmetrical breaking capacity of a circuit breaker
Rated symmetrical breaking current 
Making current of a circuit breaker is the peak value of the maximum current loop during sub transient condition including the DC component when the breaker closes.
Symmetrical making current = 2.55 × symmetrical breaking current
Calculation:
Rated current = 1500 A
MVA rating = 2000 MVA
Rated symmetrical breaking current 
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A three-phase 33 kV, oil-circuit breaker is rated 1500 A, 2000 MVA, 2 s. The symmetrical breaking current for this breakerwould bea)40 kAb)25 kAc)35 kAd)50 kACorrect answer is option 'C'. Can you explain this answer?
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