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If S = 3t2 - 5t + 7 find initial velocity.
- a)2
- b)5
- c)-2
- d)-5
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer i...
Formula Used:
Velocity = s/t
Here, S is displacement and t is time
For instantaneous velocity, it expressed as dS/dt
Application:
We have,
S = 3t2 - 5t + 7
Hence,
Instantaneous velocity = dS/dt = (6t - 5)
initial velocity will be found at t = o
Hence,
V|initial = (6 × 0 - 5) = - 5
Velocity = s/t
Here, S is displacement and t is time
For instantaneous velocity, it expressed as dS/dt
Application:
We have,
S = 3t2 - 5t + 7
Hence,
Instantaneous velocity = dS/dt = (6t - 5)
initial velocity will be found at t = o
Hence,
V|initial = (6 × 0 - 5) = - 5
Most Upvoted Answer
If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer i...
Understanding the Problem
To find the initial velocity from the given equation of motion, we focus on the position equation:
S = 3t² - 5t + 7
Here, S represents the position, and t represents time.
Identifying Initial Conditions
- The initial velocity refers to the velocity of the object at time t = 0.
- We can find the velocity by taking the derivative of the position function S with respect to time t.
Calculating the Velocity Function
- The velocity (v) is given by the derivative of S:
v(t) = dS/dt
- Taking the derivative of the equation S = 3t² - 5t + 7:
* v(t) = d(3t²)/dt - d(5t)/dt + d(7)/dt
* v(t) = 6t - 5
Finding Initial Velocity
- To find the initial velocity, substitute t = 0 into the velocity equation:
v(0) = 6(0) - 5
v(0) = -5
Conclusion
- The initial velocity of the object is -5.
- Therefore, the correct answer is option 'D'.
This detailed breakdown clarifies how to derive the initial velocity from the given position equation.
To find the initial velocity from the given equation of motion, we focus on the position equation:
S = 3t² - 5t + 7
Here, S represents the position, and t represents time.
Identifying Initial Conditions
- The initial velocity refers to the velocity of the object at time t = 0.
- We can find the velocity by taking the derivative of the position function S with respect to time t.
Calculating the Velocity Function
- The velocity (v) is given by the derivative of S:
v(t) = dS/dt
- Taking the derivative of the equation S = 3t² - 5t + 7:
* v(t) = d(3t²)/dt - d(5t)/dt + d(7)/dt
* v(t) = 6t - 5
Finding Initial Velocity
- To find the initial velocity, substitute t = 0 into the velocity equation:
v(0) = 6(0) - 5
v(0) = -5
Conclusion
- The initial velocity of the object is -5.
- Therefore, the correct answer is option 'D'.
This detailed breakdown clarifies how to derive the initial velocity from the given position equation.
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If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer is option 'D'. Can you explain this answer?
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If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer is option 'D'. Can you explain this answer? for ACT 2025 is part of ACT preparation. The Question and answers have been prepared according to the ACT exam syllabus. Information about If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for ACT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer is option 'D'. Can you explain this answer?.
If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer is option 'D'. Can you explain this answer? for ACT 2025 is part of ACT preparation. The Question and answers have been prepared according to the ACT exam syllabus. Information about If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for ACT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If S = 3t2- 5t + 7find initial velocity.a)2b)5c)-2d)-5Correct answer is option 'D'. Can you explain this answer?.
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