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At present age of Asha in years is 2 more than the square of a daughter nisha's age when Nisha grows to her mother's present age asha's age would be one year less than 10 times the present age of Nisha find the present age of both Asha and Nisha?
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At present age of Asha in years is 2 more than the square of a daughte...
Presentation:

Given:
- Present age of Asha is 2 more than the square of Nisha's age.
- When Nisha grows to her mother's present age, Asha's age would be one year less than 10 times Nisha's present age.

To find:
- Present age of both Asha and Nisha.

Solution:

Let's assume Nisha's present age as x years. Therefore, Asha's present age would be x^2 + 2 years.

When Nisha grows to her mother's present age, her age will be x + (x^2 + 2) = x^2 + x + 2 years.

According to the given information, Asha's age at that time would be one year less than 10 times Nisha's present age:
x^2 + x + 2 = 10x - 1.

Now, let's solve the above equation to find the value of x.

Step 1:
x^2 + x + 2 = 10x - 1

Step 2:
Rearranging the equation:
x^2 + x - 10x + 2 + 1 = 0
x^2 - 9x + 3 = 0

Step 3:
Using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = -9, and c = 3.

Step 4:
x = (-(-9) ± √((-9)^2 - 4(1)(3))) / (2(1))
x = (9 ± √(81 - 12)) / 2
x = (9 ± √69) / 2

Step 5:
Since age cannot be negative, we can discard the negative value.

x = (9 + √69) / 2

Step 6:
Now, we can substitute the value of x back into the equation to find Asha's present age.
Asha's present age = x^2 + 2

Conclusion:
By solving the equation, we can find the values of x and Asha's present age. Nisha's present age would be x years, and Asha's present age would be x^2 + 2 years.
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At present age of Asha in years is 2 more than the square of a daughter nisha's age when Nisha grows to her mother's present age asha's age would be one year less than 10 times the present age of Nisha find the present age of both Asha and Nisha?
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