At present age of Asha in years is 2 more than the square of a daughte...
Presentation:
Given:
- Present age of Asha is 2 more than the square of Nisha's age.
- When Nisha grows to her mother's present age, Asha's age would be one year less than 10 times Nisha's present age.
To find:
- Present age of both Asha and Nisha.
Solution:
Let's assume Nisha's present age as x years. Therefore, Asha's present age would be x^2 + 2 years.
When Nisha grows to her mother's present age, her age will be x + (x^2 + 2) = x^2 + x + 2 years.
According to the given information, Asha's age at that time would be one year less than 10 times Nisha's present age:
x^2 + x + 2 = 10x - 1.
Now, let's solve the above equation to find the value of x.
Step 1:
x^2 + x + 2 = 10x - 1
Step 2:
Rearranging the equation:
x^2 + x - 10x + 2 + 1 = 0
x^2 - 9x + 3 = 0
Step 3:
Using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = -9, and c = 3.
Step 4:
x = (-(-9) ± √((-9)^2 - 4(1)(3))) / (2(1))
x = (9 ± √(81 - 12)) / 2
x = (9 ± √69) / 2
Step 5:
Since age cannot be negative, we can discard the negative value.
x = (9 + √69) / 2
Step 6:
Now, we can substitute the value of x back into the equation to find Asha's present age.
Asha's present age = x^2 + 2
Conclusion:
By solving the equation, we can find the values of x and Asha's present age. Nisha's present age would be x years, and Asha's present age would be x^2 + 2 years.