Three resistors 5Ω, 10Ω and 30Ω are connected in parallel with the ba...
The value of current across each resistor:
- In a parallel circuit, the voltage across each resistor is the same.
- Using Ohm's Law (V = IR), we can calculate the current across each resistor by dividing the voltage (6V) by the resistance of each resistor.
- Therefore, the current across the 5Ω resistor is 6V/5Ω = 1.2A, across the 10Ω resistor is 6V/10Ω = 0.6A, and across the 30Ω resistor is 6V/30Ω = 0.2A.
The value of Potential difference across each resistor:
- As mentioned earlier, the voltage across each resistor is the same in a parallel circuit.
- Therefore, the potential difference across the 5Ω resistor is 6V, across the 10Ω resistor is 6V, and across the 30Ω resistor is 6V.
Total current in the circuit:
- In a parallel circuit, the total current is the sum of the currents flowing through each individual resistor.
- Therefore, the total current in the circuit is 1.2A + 0.6A + 0.2A = 2A.
Effective resistance of the circuit:
- In a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances.
- Therefore, the effective resistance (R) of the circuit can be calculated using the formula: 1/R = 1/5Ω + 1/10Ω + 1/30Ω.
- Simplifying this equation gives us: 1/R = (6/30) + (6/60) + (6/180) = 0.2 + 0.1 + 0.033 = 0.333.
- Taking the reciprocal of both sides, we find: R = 1/0.333 = 3Ω.
- Therefore, the effective resistance of the circuit is 3Ω.
In summary:
1. The value of current across each resistor: 1.2A, 0.6A, and 0.2A.
2. The value of Potential difference across each resistor: 6V, 6V, and 6V.
3. Total current in the circuit: 2A.
4. Effective resistance of the circuit: 3Ω.