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Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR?
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Two batteries of EMF for old and 8 volt with internal resistance 1 ohm...
Calculating Current and Potential Difference in the Circuit
Given Data:
- EMF of old battery: 8V
- Internal resistance of old battery: 1 ohm
- Internal resistance of new battery: 2 ohm
- Resistance in the circuit: 9 ohm
Calculating Equivalent EMF and Internal Resistance:
- The equivalent EMF of the two batteries in series is: E = E1 + E2 = 8V + 8V = 16V
- The equivalent internal resistance of the two batteries in series is: r = r1 + r2 = 1 ohm + 2 ohm = 3 ohm
Calculating Total Resistance in the Circuit:
- The total resistance in the circuit is: R_total = R + r = 9 ohm + 3 ohm = 12 ohm
Calculating Current in the Circuit using Ohm's Law:
- The total current in the circuit is: I = E / R_total = 16V / 12 ohm = 1.33A
Calculating Potential Difference between Points P and QR:
- The potential difference across the resistance of 9 ohm is: V = I * R = 1.33A * 9 ohm = 12V
Therefore, the current in the circuit is 1.33A and the potential difference between points P and QR is 12V.
Given Data:
- EMF of old battery: 8V
- Internal resistance of old battery: 1 ohm
- Internal resistance of new battery: 2 ohm
- Resistance in the circuit: 9 ohm
Calculating Equivalent EMF and Internal Resistance:
- The equivalent EMF of the two batteries in series is: E = E1 + E2 = 8V + 8V = 16V
- The equivalent internal resistance of the two batteries in series is: r = r1 + r2 = 1 ohm + 2 ohm = 3 ohm
Calculating Total Resistance in the Circuit:
- The total resistance in the circuit is: R_total = R + r = 9 ohm + 3 ohm = 12 ohm
Calculating Current in the Circuit using Ohm's Law:
- The total current in the circuit is: I = E / R_total = 16V / 12 ohm = 1.33A
Calculating Potential Difference between Points P and QR:
- The potential difference across the resistance of 9 ohm is: V = I * R = 1.33A * 9 ohm = 12V
Therefore, the current in the circuit is 1.33A and the potential difference between points P and QR is 12V.
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Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR?
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Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR?.
Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two batteries of EMF for old and 8 volt with internal resistance 1 ohm and two ohm are connected in the circuit with the resistance of 9 ohm and show the current and potential difference between the points p and QR?.
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