UPSC Exam > UPSC Questions > A 200 ohm resistor a voltmeter and a 2v cell ...
Start Learning for Free
A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit?
Most Upvoted Answer
A 200 ohm resistor a voltmeter and a 2v cell of negligible internal re...
Resistance of the Voltmeter:
- The voltmeter and the 200 ohm resistor are connected in series with the 2V cell.
- The voltmeter reads 1V, which means that the voltage drop across the voltmeter is 1V.
- The total voltage drop in the circuit is 2V (voltage of the cell).
- Therefore, the voltage drop across the 200 ohm resistor is 2V - 1V = 1V.
- Using Ohm's Law (V = IR), we can find the current flowing through the circuit.
Current in the Circuit:
- The voltage drop across the 200 ohm resistor is 1V.
- Using Ohm's Law (V = IR), we can calculate the current flowing through the resistor.
- I = V/R = 1V / 200 ohm = 0.005A = 5mA.
- Since the voltmeter is connected in series with the resistor, the current flowing through the voltmeter is the same as the current flowing through the resistor.
- Therefore, the current in the circuit is 5mA.
By analyzing the given information and applying Ohm's Law, we can determine the resistance of the voltmeter and the current flowing through the circuit. The resistance of the voltmeter is not explicitly given but can be calculated based on the voltage reading and the total circuit voltage. The current flowing through the circuit can then be calculated using the resistance of the voltmeter and the total circuit voltage.
- The voltmeter and the 200 ohm resistor are connected in series with the 2V cell.
- The voltmeter reads 1V, which means that the voltage drop across the voltmeter is 1V.
- The total voltage drop in the circuit is 2V (voltage of the cell).
- Therefore, the voltage drop across the 200 ohm resistor is 2V - 1V = 1V.
- Using Ohm's Law (V = IR), we can find the current flowing through the circuit.
Current in the Circuit:
- The voltage drop across the 200 ohm resistor is 1V.
- Using Ohm's Law (V = IR), we can calculate the current flowing through the resistor.
- I = V/R = 1V / 200 ohm = 0.005A = 5mA.
- Since the voltmeter is connected in series with the resistor, the current flowing through the voltmeter is the same as the current flowing through the resistor.
- Therefore, the current in the circuit is 5mA.
By analyzing the given information and applying Ohm's Law, we can determine the resistance of the voltmeter and the current flowing through the circuit. The resistance of the voltmeter is not explicitly given but can be calculated based on the voltage reading and the total circuit voltage. The current flowing through the circuit can then be calculated using the resistance of the voltmeter and the total circuit voltage.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Top Courses for UPSCView all
A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit?
Question Description
A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit?.
A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit?.
Solutions for A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? defined & explained in the simplest way possible. Besides giving the explanation of
A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit?, a detailed solution for A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? has been provided alongside types of A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? theory, EduRev gives you an
ample number of questions to practice A 200 ohm resistor a voltmeter and a 2v cell of negligible internal resistance are connected in series.the voltmeter reads 1V.find the resistance of the voltmeter and the current in the circuit? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup