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The graph of the polynomial 2x2-8x+5 cuts the y-axis at 
  • a)
    (8, 9)
  • b)
    (0, 5)
  • c)
    (0, 7)
  • d)
    (6, 0)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The graph of the polynomial 2x2-8x+5 cuts the y-axis ata)(8, 9)b)(0, 5...
Clarification: The graph of the polynomial 2x2-8x+5 cuts the y-axis.
Hence, the value of x will be 0.
y(0)=2(0)2-8(0)+5
y=5
The graph cuts the y-axis at (0,5)
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Most Upvoted Answer
The graph of the polynomial 2x2-8x+5 cuts the y-axis ata)(8, 9)b)(0, 5...
Graph of the Polynomial:
The given polynomial is 2x^2 - 8x + 5. To find the y-intercept, we need to substitute x = 0 into the polynomial equation and solve for y.

Substituting x = 0 into the equation:
2(0)^2 - 8(0) + 5 = 5

Therefore, the y-intercept is (0, 5).

Explanation:
The y-intercept is the point where the graph of a polynomial intersects the y-axis. In other words, it is the point where the value of x is 0. To find the y-intercept, we substitute x = 0 into the polynomial equation and solve for y.

In this case, when we substitute x = 0 into the equation 2x^2 - 8x + 5, we get:

2(0)^2 - 8(0) + 5 = 5

Therefore, the y-intercept is (0, 5), which means that the graph of the polynomial intersects the y-axis at the point (0, 5).

Conclusion:
The correct answer is option 'B' (0, 5) because the graph of the polynomial 2x^2 - 8x + 5 intersects the y-axis at the point (0, 5).
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