The equation of the tangent to the curve f= x^2 - 3x + 2, at the point...
Equation of Tangent to Curve
To find the equation of the tangent to the curve f= x^2 - 3x 2, at the point (2,7) we need to follow the given steps:
Step 1: Find the Derivative
The slope of the tangent is given by the derivative of the function f(x) at the point (2,7). Therefore, we need to find the derivative of x^2 - 3x + 2.
f(x) = x^2 - 3x + 2
f'(x) = 2x - 3
Step 2: Find the Slope of the Tangent
Now, we can find the slope of the tangent at point (2,7) by substituting x = 2 in the derivative.
f'(2) = 2(2) - 3 = 1
Therefore, the slope of the tangent at point (2,7) is 1.
Step 3: Use Point-Slope Form to Find the Equation of the Tangent
The equation of the tangent at point (2,7) can be found using the point-slope form of a line.
y - y1 = m(x - x1)
Where (x1,y1) is the point on the line and m is the slope of the line.
Substituting the values of (x1,y1) = (2,7) and m = 1, we get:
y - 7 = 1(x - 2)
Therefore, the equation of the tangent to the curve f= x^2 - 3x + 2, at the point (2,7) is y = x + 5.
Step 4: Verify the Result
We can verify the result by graphing the curve and the tangent line. The graph confirms that the tangent line passes through the point (2,7) and touches the curve at that point.