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Can you explain the answer of this question below:
The maximum amount of BaCl₄ precipitated on mixing BaCl₂ (0.5 M) with H₂SO₄ (1M) will correspond to
  • A:
    0.5 M
  • B:
    1.0 M
  • C:
    1.5 M
  • D:
    2.0 M
The answer is a.
Most Upvoted Answer
Can you explain the answer of this question below:The maximum amount o...
1. The options provided by you are all in kg,and incorrect too. In question it is asked that amount BaSO4 in terms of moles.2. The reaction is : BaCl2 + H2SO4 →→ BaSO4 + 2HCl3. 1 mole of BaCl2 reacts with 1 mole of H2SO4 to give 1 mole of BaSO4. But here 0.5 M of BaCl2 is present for 1 mole of H2SO4.So.BaCl2 is the limiting reagent,and 0.5M of BaSO4 is obtained.
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Can you explain the answer of this question below:The maximum amount o...
Understanding the Reaction
When barium chloride (BaCl2) reacts with sulfuric acid (H2SO4), barium sulfate (BaSO4) is formed as a precipitate. The balanced chemical equation for this reaction is:
BaCl2 + H2SO4 → BaSO4 (s) + 2 HCl
Identifying Reactants
- Available Moles: In this scenario, we have:
- 0.5 moles of BaCl2
- 1 mole of H2SO4
- Stoichiometry: The reaction shows that 1 mole of BaCl2 reacts with 1 mole of H2SO4 to produce 1 mole of BaSO4.
Limiting Reagent Analysis
- Limiting Reagent: Since the reaction requires equal moles of BaCl2 and H2SO4, we need to identify the limiting reagent.
- Comparison:
- 0.5 moles of BaCl2 can react with 0.5 moles of H2SO4.
- 1 mole of H2SO4 is more than enough to react with the given 0.5 moles of BaCl2.
Thus, BaCl2 is the limiting reagent.
Calculating Maximum BaSO4 Produced
- Since BaCl2 is the limiting reagent and it produces BaSO4 in a 1:1 ratio, the maximum amount of BaSO4 formed is equal to the amount of BaCl2 available:
- BaSO4 Produced: 0.5 moles of BaSO4.
Conclusion
- The maximum amount of BaSO4 that can be obtained from mixing 0.5 moles of BaCl2 with 1 mole of H2SO4 is 0.5 moles.
The correct answer is therefore option A.
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