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An object 2 cm high is placed at a distance of 15 cm from a concave mirror which produces an inverted image 4 cm high. Find the position of the image.

  • a)
    -30 cm

  • b)
    30 cm

  • c)
    40 cm

  • d)
    -40 cm

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An object 2 cm high is placed at a distance of 15 cm from a concave mi...
The magnification produced by a concave mirror is given by the formula:


m = -v/u


where, m = magnification v = image distance u = object distance


From the problem, we have: u = -15 cm (since the object is placed in front of the mirror, the distance is negative) m = -4/2 = -2 (since the image is inverted and 4 cm high whereas the object is 2 cm high)


Substituting these values in the magnification formula, we get:


-2 = -v/(-15)


Simplifying, we get:


v = 30 cm


Therefore, the position of the image is 30 cm from the concave mirror.
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Most Upvoted Answer
An object 2 cm high is placed at a distance of 15 cm from a concave mi...
Given:
Height of object (h1) = 2 cm
Distance of object (u) = -15 cm (as it is in front of mirror)
Height of image (h2) = -4 cm (as it is inverted)
Formula used:
Mirror formula:
1/f = 1/v + 1/u
Magnification formula:
m = -v/u = h2/h1

Calculation:
Using the magnification formula:
m = -v/u = h2/h1
⇒ -v/-15 = -4/2
⇒ v = -30 cm (as v is negative, it means the image is formed behind the mirror)

Therefore, the position of the image is 30 cm from the concave mirror, which is option B.
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An object 2 cm high is placed at a distance of 15 cm from a concave mi...
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