Can you explain the answer of this question below:A woman with albinic...
Given information:
- The woman has an albinic father, which means she carries the albino gene.
- She marries an albinic man, who also carries the albino gene.
Explanation:
The woman's genotype for the albino gene is Aa (A represents the normal gene, and a represents the albino gene). The albinic man's genotype is also Aa.
When they have offspring, the possible combinations of their genes are:
- AA (normal) from the woman and AA (normal) from the man
- AA (normal) from the woman and Aa (carrier) from the man
- Aa (carrier) from the woman and AA (normal) from the man
- Aa (carrier) from the woman and Aa (carrier) from the man
Calculations:
The Punnett square can be used to determine the probability of each genotype.
- When both parents have the genotype Aa, the possible offspring genotypes are AA, Aa, and aa. The probability of each genotype is 1/4 for AA, 1/2 for Aa, and 1/4 for aa.
Conclusion:
Based on the calculations, the proportion of her progeny will be 1 normal : 1 albinic (Aa : aa), which corresponds to option D: 1 normal : 1 albinic.
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Can you explain the answer of this question below:A woman with albinic...
Can you explain the answer of this question below:A woman with albinic...
A woman has albinism father it means that she must be carrier for the trait .also , she marries albinic man . It means,,, X¤X ×X¤Y so on crossing there will be half progenies as normal and remaining having disease....