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A capacitor 100μF, and inductor 16H and a resistor 100 Ω are connected in series across an ac source of E = 200 sin 25t the power dissipated in the circuit isa)400Wb)200Wc)100Wd)600WCorrect answer is 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A capacitor 100μF, and inductor 16H and a resistor 100 Ω are connected in series across an ac source of E = 200 sin 25t the power dissipated in the circuit isa)400Wb)200Wc)100Wd)600WCorrect answer is 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capacitor 100μF, and inductor 16H and a resistor 100 Ω are connected in series across an ac source of E = 200 sin 25t the power dissipated in the circuit isa)400Wb)200Wc)100Wd)600WCorrect answer is 'B'. Can you explain this answer?.

Solutions for A capacitor 100μF, and inductor 16H and a resistor 100 Ω are connected in series across an ac source of E = 200 sin 25t the power dissipated in the circuit isa)400Wb)200Wc)100Wd)600WCorrect answer is 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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