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 If 4 is a root of the equation , then k is​
  • a)
    -28
  • b)
    -12
  • c)
    12
  • d)
    28
Correct answer is 'A'. Can you explain this answer?
Verified Answer
If 4 is a root of the equation, then k is​a)-28b)-12c)12d)28Corr...
4 is the solution , this means that if we put x=4 we get 0. So putting x=4 in the equation x2+3x+k=0 we get 42+3*4+k=0
16+12+k=0 ⇒ k=-28
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Most Upvoted Answer
If 4 is a root of the equation, then k is​a)-28b)-12c)12d)28Corr...
A =-28 is correct because 4 is the root or zero of the given linear equation so if you replace x by 4 then you will get the value of K. P(4)=0 4^2+3×4+k=0 16+12+k=0 So, k=-28
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Community Answer
If 4 is a root of the equation, then k is​a)-28b)-12c)12d)28Corr...
Because 4 is the root of equation let X=4 then, (4)2+3×4+k=0, 16+12+k=0, 28+k=0 k=—28
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If 4 is a root of the equation, then k is​a)-28b)-12c)12d)28Correct answer is 'A'. Can you explain this answer?
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