Can you explain the answer of this question below:The phenotypic ratio...
Explanation:
In a dihybrid cross, two traits are considered simultaneously. The F1 generation produced after crossing two pure breeding lines will all be heterozygous for both traits.
For example, if two pure breeding plants with yellow round seeds (YYRR) are crossed with plants with green wrinkled seeds (yyrr), the F1 generation will all be heterozygous for both traits (YyRr).
When the F1 generation is crossed with itself or another F1 individual, the resulting F2 generation will exhibit all possible combinations of the two traits.
The phenotypic ratio in the F2 generation of a dihybrid cross is determined by the number of possible combinations of the two traits.
The possible combinations of the two traits can be determined using a Punnett square or the FOIL method.
For example, using the FOIL method:
(YyRr) x (YyRr)
YYRr YyRR YyRr yyRR
YYRr YyRR YyRr yyRR
YyRr yyRR YyRr yyrr
yyRR yyRR yyrr yyrr
In this example, there are 9 individuals with both dominant traits (yellow and round seeds), 3 individuals with one dominant and one recessive trait (yellow and wrinkled seeds, green and round seeds), and 1 individual with both recessive traits (green and wrinkled seeds).
Therefore, the phenotypic ratio in the F2 generation of this dihybrid cross is 9:3:3:1, which is option B.
Can you explain the answer of this question below:The phenotypic ratio...
Because it produces produced nine plants with round, yellow seeds, three plants with round, green seeds, three plants with wrinkled, yellow seeds and one plant with wrinkled, green seeds.therefore the ratio is 9:3:3:1