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One of the roots of the quadratic equation 6x2 – x – 2 = 0 is:
- a)-2/3
- b)-1/2
- c)1/2
- d)-1
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
One of the roots of the quadratic equation 6x2– x – 2 = 0 ...
Since the equation is 6x²- x-2 ....Using splitting middle term, 6x²-4x+3x-2 then, 2x(3x-2)+1(3x-2)....(2x+1) (3x-2)..So the roots r : x =-1/2 & x =2/3...So answr b is right.
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One of the roots of the quadratic equation 6x2– x – 2 = 0 ...
Solution:
Given quadratic equation is 6x^2 + x - 2 = 0.
We need to find out one of the roots of the given equation.
We can solve the quadratic equation by using the quadratic formula.
Quadratic Formula:
For the quadratic equation ax^2 + bx + c = 0, the quadratic formula is given by
x = (-b ± √(b^2 - 4ac)) / (2a)
Here, a = 6, b = 1 and c = -2.
Substituting the values in the quadratic formula, we get
x = (-1 ± √(1^2 - 4(6)(-2))) / (2(6))
x = (-1 ± √(1 + 48)) / 12
x = (-1 ± √49) / 12
x = (-1 ± 7) / 12
Therefore, the roots of the quadratic equation are
x = (-1 + 7) / 12 = 6/12 = 1/2 and
x = (-1 - 7) / 12 = -8/12 = -2/3
Hence, one of the roots of the quadratic equation 6x^2 + x - 2 = 0 is -2/3.
Therefore, the correct option is (a) -2/3.
Given quadratic equation is 6x^2 + x - 2 = 0.
We need to find out one of the roots of the given equation.
We can solve the quadratic equation by using the quadratic formula.
Quadratic Formula:
For the quadratic equation ax^2 + bx + c = 0, the quadratic formula is given by
x = (-b ± √(b^2 - 4ac)) / (2a)
Here, a = 6, b = 1 and c = -2.
Substituting the values in the quadratic formula, we get
x = (-1 ± √(1^2 - 4(6)(-2))) / (2(6))
x = (-1 ± √(1 + 48)) / 12
x = (-1 ± √49) / 12
x = (-1 ± 7) / 12
Therefore, the roots of the quadratic equation are
x = (-1 + 7) / 12 = 6/12 = 1/2 and
x = (-1 - 7) / 12 = -8/12 = -2/3
Hence, one of the roots of the quadratic equation 6x^2 + x - 2 = 0 is -2/3.
Therefore, the correct option is (a) -2/3.
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One of the roots of the quadratic equation 6x2– x – 2 = 0 is:a)-2/3b)-1/2c)1/2d)-1Correct answer is option 'B'. Can you explain this answer?
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