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 Two simple harmonic motions are represented by y1=4sin(πt– π/2) and y2=3cos(4πt). The resultant amplitude is
  • a)
    /
  • b)
    1
  • c)
    5
  • d)
    2+√3
Correct answer is 'A'. Can you explain this answer?
Most Upvoted Answer
Two simple harmonic motions are represented byy1=4sin(πt– &pi...
/\ is 0 in that case so the resulted amplitude will be A1+A2 that equal to 7
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Community Answer
Two simple harmonic motions are represented byy1=4sin(πt– &pi...
Option 1 is not clear visible .pls send again
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Two simple harmonic motions are represented byy1=4sin(πt– π/2) andy2=3cos(4πt). The resultant amplitude isa)/b)1c)5d)2+√3Correct answer is 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two simple harmonic motions are represented byy1=4sin(πt– π/2) andy2=3cos(4πt). The resultant amplitude isa)/b)1c)5d)2+√3Correct answer is 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two simple harmonic motions are represented byy1=4sin(πt– π/2) andy2=3cos(4πt). The resultant amplitude isa)/b)1c)5d)2+√3Correct answer is 'A'. Can you explain this answer?.
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