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A 100 mH coil carries a current of 10 A. The magnetic energy stored in the coil is
- a)0.1 J
- b)0.5 J
- c)1 J
- d)5 J
Correct answer is 'D'. Can you explain this answer?
Most Upvoted Answer
A 100 mH coil carries a current of 10 A. The magnetic energy stored in...
Solution:
Given,
Inductance, L = 100mH = 0.1 H
Current, I = 10A
The magnetic energy stored in an inductor is given as:
W = 1/2 LI^2
Substituting the given values, we get:
W = 1/2 x 0.1 x (10)^2
W = 5J
Therefore, the magnetic energy stored in the coil is 5J, which is option D.
Explanation:
The magnetic energy stored in an inductor is the energy required to establish a magnetic field around it when a current flows through it. This energy is stored in the form of a magnetic field around the inductor and is given by the formula W = 1/2 LI^2.
The inductance of the coil measures the amount of magnetic energy stored in the coil when a current flows through it. The unit of inductance is Henry (H) and is defined as the amount of inductance when a current of 1 ampere flows through a coil and produces a magnetic flux of 1 weber.
The current flowing through the coil also determines the magnetic energy stored in it. The higher the current, the higher the magnetic energy stored in the coil.
In this problem, the inductance of the coil is given as 100mH or 0.1H and the current flowing through it is 10A. Using the formula W = 1/2 LI^2, we can calculate the magnetic energy stored in the coil, which is 5J.
Given,
Inductance, L = 100mH = 0.1 H
Current, I = 10A
The magnetic energy stored in an inductor is given as:
W = 1/2 LI^2
Substituting the given values, we get:
W = 1/2 x 0.1 x (10)^2
W = 5J
Therefore, the magnetic energy stored in the coil is 5J, which is option D.
Explanation:
The magnetic energy stored in an inductor is the energy required to establish a magnetic field around it when a current flows through it. This energy is stored in the form of a magnetic field around the inductor and is given by the formula W = 1/2 LI^2.
The inductance of the coil measures the amount of magnetic energy stored in the coil when a current flows through it. The unit of inductance is Henry (H) and is defined as the amount of inductance when a current of 1 ampere flows through a coil and produces a magnetic flux of 1 weber.
The current flowing through the coil also determines the magnetic energy stored in it. The higher the current, the higher the magnetic energy stored in the coil.
In this problem, the inductance of the coil is given as 100mH or 0.1H and the current flowing through it is 10A. Using the formula W = 1/2 LI^2, we can calculate the magnetic energy stored in the coil, which is 5J.
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A 100 mH coil carries a current of 10 A. The magnetic energy stored in the coil isa)0.1 Jb)0.5 Jc)1 Jd)5 JCorrect answer is 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 100 mH coil carries a current of 10 A. The magnetic energy stored in the coil isa)0.1 Jb)0.5 Jc)1 Jd)5 JCorrect answer is 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100 mH coil carries a current of 10 A. The magnetic energy stored in the coil isa)0.1 Jb)0.5 Jc)1 Jd)5 JCorrect answer is 'D'. Can you explain this answer?.
A 100 mH coil carries a current of 10 A. The magnetic energy stored in the coil isa)0.1 Jb)0.5 Jc)1 Jd)5 JCorrect answer is 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 100 mH coil carries a current of 10 A. The magnetic energy stored in the coil isa)0.1 Jb)0.5 Jc)1 Jd)5 JCorrect answer is 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100 mH coil carries a current of 10 A. The magnetic energy stored in the coil isa)0.1 Jb)0.5 Jc)1 Jd)5 JCorrect answer is 'D'. Can you explain this answer?.
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