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Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:?
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Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x)...
Understanding the Function:
The given function f(x) = (3x - 2) ÷ (x + 1) can be rewritten as f(x) = 3 - 5/(x + 1). This function has a vertical asymptote at x = -1 due to the denominator being 0 at that point. As x approaches -1 from the left, f(x) approaches negative infinity, and as x approaches -1 from the right, f(x) approaches positive infinity.
Finding the Maximum Integral Value:
To find the largest integral value of y = f(x), we need to observe the behavior of the function as x approaches -1. As x approaches -1 from the left, f(x) approaches negative infinity, and as x approaches -1 from the right, f(x) approaches positive infinity. Therefore, the function has no maximum integral value.
Conclusion:
Since the function f(x) = (3x - 2) ÷ (x + 1) has no maximum integral value due to its behavior around x = -1, the largest integral value of y = f(x) does not exist.
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Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:?
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Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:?.
Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider, f(x) = (3x -2) ÷ (x+1). The largest integral value of y=f(x) is:?.
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