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2â = 3power b = 12 power c then 1/c-1/b-2la reduce to?
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2â = 3power b = 12 power c then 1/c-1/b-2la reduce to?

Given Information:


- 2^a = 3^b = 12^c


To find:


- The value of 1/(c-1) - 1/(b-2)


Solution:



Step 1: Finding the values of a, b, and c


- Since 2^a = 3^b, we can equate the exponents:
- a = log(base 2) 3 * b

- Similarly, since 3^b = 12^c, we can equate the exponents:
- b = log(base 3) 12 * c

- Substitute the value of b in terms of c into the equation a = log(base 2) 3 * b:
- a = log(base 2) 3 * [log(base 3) 12 * c]


Step 2: Simplifying the expression 1/(c-1) - 1/(b-2)


- Substitute the values of a and b in terms of c into the expression:
- 1/(c-1) - 1/([log(base 3) 12 * c]-2)

- Simplify the expression further to get the final answer.


Final Answer:


- After simplifying the expression, the final reduced form of 1/(c-1) - 1/(b-2) will be the answer.
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2â = 3power b = 12 power c then 1/c-1/b-2la reduce to?
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