In a school, 37.5% of the students are girls and rest are boys. If 80% of the girls and 70% of the boys participated in annual sports of the school, what percent of the total number of students in the school did not participate in that event?a)20.5%b)16.25%c)12.5%d)26.25%Correct answer is option 'D'. Can you explain this answer?

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In a school, 37.5% of the students are girls and rest are boys. If 80% of the girls and 70% of the boys participated in annual sports of the school, what percent of the total number of students in the school did not participate in that event?

a)
20.5%
b)
16.25%
c)
12.5%
d)
26.25%

Correct answer is option 'D'. Can you explain this answer?

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Most Upvoted Answer

In a school, 37.5% of the students are girls and rest are boys. If 80%...

Given Data:
- 37.5% of students are girls
- 80% of girls participated in annual sports
- 70% of boys participated in annual sports

Calculating the Percentages:
- Let's assume there are 100 students in the school. So, 37.5 girls and 62.5 boys.
- Number of girls participating = 37.5 * 0.8 = 30
- Number of boys participating = 62.5 * 0.7 = 43.75 (approx. 44)

Calculating the Total Number of Participants:
- Total number of students participating = 30 (girls) + 44 (boys) = 74

Calculating the Percentage of Students Not Participating:
- Total students in the school = 100
- Number of students not participating = 100 - 74 = 26
- Percentage of students not participating = (26/100) * 100 = 26%
Therefore, the correct answer is option D) 26.25%.

Answered by Notes Wala · View profile

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Community Answer

In a school, 37.5% of the students are girls and rest are boys. If 80%...

37.5% = 3/8
Let the total number of students in the school be 80x.
So, the number of girls in the school = 80x × 3/8 = 30x
And, the number of boys in the school = 80x - 30x = 50x
80% of the girls and 70% of the boys participated in annual sports of the school. So, the number of girls who did not participate in annual sports = 30x × (100 – 80)% = 30x × (20/100) = 6x
And the number of boys who did not participate in annual sports = 50x × (100 – 70)% = 50x × (30/100) = 15x
otal number of students who did not participate in annual sports = 6x + 15x = 21x
Required percentage = (21x/80x) × 100 = 26.25%

Hence, option (d) is correct.

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