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Three generators rated 100 MVA, 11 kV have an impedance of 0.15pu each. If in the same plant, these generators are being replaced by a single equivalent generator, the effective impedance of equivalent generator will be
  • a)
    0.05 pu
  • b)
    0.15 pu
  • c)
    0.25 pu
  • d)
    0.45 pu
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Three generators rated 100 MVA, 11 kV have an impedance of 0.15pu each...
Given impedance value = 0.15 pu
When three generators are replaced by a single generator, their impedance are connected parallelly. So, their equivalent impedance will be one-third of each impedance.
New impedance = 0.15/3 = 0.05 pu
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Most Upvoted Answer
Three generators rated 100 MVA, 11 kV have an impedance of 0.15pu each...
Given:
- Three generators rated 100 MVA, 11 kV each
- Impedance of each generator = 0.15 pu

To find:
- Effective impedance of the single equivalent generator

Solution:

When generators are connected in parallel, their impedances add up. To find the equivalent impedance of the single generator, we need to calculate the total impedance of the three generators.

Step 1: Calculate the total impedance of three generators:
- Impedance of each generator = 0.15 pu
- Total impedance of three generators = 3 * 0.15 pu = 0.45 pu

Step 2: Calculate the equivalent impedance of the single generator:
- Equivalent impedance = Total impedance / Number of generators
- Equivalent impedance = 0.45 pu / 3 = 0.15 pu

Therefore, the effective impedance of the single equivalent generator is 0.15 pu.

Conclusion:
When three generators with an impedance of 0.15 pu each are replaced by a single equivalent generator, the effective impedance of the equivalent generator is 0.15 pu.
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