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The half life of a first order reaction is 2000 years if the concentration after 8000 years is 0.02 then the initial concentration was?
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The half life of a first order reaction is 2000 years if the concentra...
Given Data:
- Half-life of the first-order reaction = 2000 years
- Concentration after 8000 years = 0.02

Calculating the rate constant (k):
- The half-life of a first-order reaction is given by the equation:
T1/2 = ln(2)/k
- Substituting the given half-life value:
2000 = ln(2)/k
k = ln(2)/2000
k ≈ 0.0003466 years^-1

Calculating the initial concentration:
- The first-order rate equation is given by:
ln([A]0/[A]t) = kt
- Substituting the given values at t=8000 years:
ln([A]0/0.02) = 0.0003466 * 8000
ln([A]0/0.02) = 2.7728
[A]0/0.02 = e^2.7728
[A]0 ≈ 15.97

Conclusion:
- The initial concentration of the reactant in the first-order reaction was approximately 15.97.
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The half life of a first order reaction is 2000 years if the concentration after 8000 years is 0.02 then the initial concentration was?
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