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If all those numbers from 1-40 each of which is exactly divisible by 4 and/or has 4 as a digit in it are removed, how many numbers will remain?
  • a)
    27
  • b)
    29
  • c)
    28
  • d)
    26
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If all those numbers from 1-40 each of which is exactly divisible by 4...
Numbers exactly divisible by4 are table of 4 and 14 , 34 have 4 as a digit so the numbers which left are 40 _ 12 = 28.

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Most Upvoted Answer
If all those numbers from 1-40 each of which is exactly divisible by 4...
Understanding the Problem
To solve the problem, we need to identify numbers from 1 to 40 that are either divisible by 4 or contain the digit 4. Once we remove these numbers, we can count how many remain.
Step 1: Identify Numbers Divisible by 4
Numbers divisible by 4 from 1 to 40 are:
- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
Total: 10 numbers
Step 2: Identify Numbers Containing the Digit 4
Numbers containing the digit 4 from 1 to 40 are:
- 4, 14, 24, 34
Total: 4 numbers
Step 3: Count Duplicates
Among the identified numbers, 4 and 24 appear in both groups. We need to ensure we only count them once.
Unique Numbers to Remove
Thus, the unique numbers to remove are:
- From divisibles by 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40 (10 total)
- From containing digit 4: 14, 34 (2 new, since 4, 24 are already counted)
Combining these gives us:
- 4, 8, 12, 14, 16, 20, 24, 28, 32, 34, 36, 40
Total unique removals: 12
Step 4: Calculate Remaining Numbers
Total numbers from 1 to 40 = 40
Remaining numbers = 40 - 12 = 28
Conclusion
Therefore, after removing all numbers that are either divisible by 4 or contain the digit 4, 28 numbers remain. Thus, the correct answer is option 'C'.
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Community Answer
If all those numbers from 1-40 each of which is exactly divisible by 4...
Numbers exactly divisible by 4 are table of 4 and 14 are 34 have 4 as a digit so the numbers which left are 40 -12 = 28.
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