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The sides of the triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is:?
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The sides of the triangle are 56 cm, 60 cm and 52 cm long. Then the ar...
Calculation of the Area of the Triangle
To find the area of the triangle with sides 56 cm, 60 cm, and 52 cm, we can use Heron's formula.

Heron's Formula
Heron's formula is given by:
\[ \text{Area} = \sqrt{s(s-a)(s-b)(s-c)} \]
where \( a \), \( b \), and \( c \) are the sides of the triangle, and \( s \) is the semi-perimeter of the triangle given by:
\[ s = \frac{a + b + c}{2} \]
In this case, the sides of the triangle are 56 cm, 60 cm, and 52 cm. So, we have:
\( a = 56 \) cm, \( b = 60 \) cm, \( c = 52 \) cm
Calculating the semi-perimeter \( s \):
\[ s = \frac{56 + 60 + 52}{2} = 84 \text{ cm} \]
Now, substituting the values into Heron's formula:
\[ \text{Area} = \sqrt{84(84-56)(84-60)(84-52)} \]
\[ \text{Area} = \sqrt{84 \times 28 \times 24 \times 32} \]
\[ \text{Area} = \sqrt{1806336} \]
\[ \text{Area} \approx 1343.73 \text{ sq cm} \]
Therefore, the area of the triangle with sides 56 cm, 60 cm, and 52 cm is approximately 1343.73 square centimeters.
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The sides of the triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is:?
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