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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?
- a)diverging lens of power +1.25 D
- b)converging lens of power +1.25 D
- c)diverging lens of power -1.25 D
- d)converging lens of power -1.25 D
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The far point of a myopic person is 80 cm in front of the eye. What is...
Far point of the defective eye, v = -80 cm
Object distance, u = -∞ (-infinity)
To find :
Nature and power of the corrective lens.
Solution :
1/v - 1/u = 1/f
1/f = 1/(-80) - 1/(-∞)
1/f = - 1/80 + 0 [Since, 1/-∞ = 0]
1/f = - 1/80
f = -80 cm
Therefore, the corrective lens should be of the focal length 80 cm.
Power, P = 1 / focal length
As focal length is in centimetres, 1 m = 100 cm.
P = 100 / -80
P = -1.25 D
Therefore, the corrective lens is diverging or concave lens of power -1.5 D.
Most Upvoted Answer
The far point of a myopic person is 80 cm in front of the eye. What is...
The corrective lens is diverging or concave lens of power -1.25 D.
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The far point of a myopic person is 80 cm in front of the eye. What is...
To correct myopia, a diverging lens is required. Let's understand this in detail.
1. Understanding Myopia:
Myopia, also known as nearsightedness, is a refractive error where the individual can see nearby objects clearly but has difficulty focusing on distant objects. In myopia, the image is formed in front of the retina instead of directly on it.
2. Far Point:
The far point is the maximum distance at which a myopic person can see objects clearly without any optical aid. In this case, the far point is given as 80 cm in front of the eye.
3. Corrective Lens:
To correct myopia, a diverging lens is used. A diverging lens is thinner in the center and thicker at the edges. It disperses light rays and causes them to diverge, which helps move the image back to the retina.
4. Lens Power:
The power of a lens is measured in diopters (D). It indicates the ability of the lens to converge or diverge light. A positive power indicates a converging lens, and a negative power indicates a diverging lens.
5. Determining the Lens Power:
To determine the lens power required to correct myopia, we use the formula:
Lens Power (P) = 1 / Focal Length (f)
The focal length is the distance from the lens to the point where parallel light rays converge or diverge.
In this case, the far point is 80 cm in front of the eye. Since the far point is before the retina, a diverging lens is required to move it back to the retina. So, the lens power should be negative.
Using the formula, we calculate:
P = 1 / (-0.8) = -1.25 D
Therefore, the nature and power of the lens required to correct the myopic person's far point of 80 cm in front of the eye is a diverging lens of power -1.25 D.
Hence, the correct answer is option C - a diverging lens of power -1.25 D.
1. Understanding Myopia:
Myopia, also known as nearsightedness, is a refractive error where the individual can see nearby objects clearly but has difficulty focusing on distant objects. In myopia, the image is formed in front of the retina instead of directly on it.
2. Far Point:
The far point is the maximum distance at which a myopic person can see objects clearly without any optical aid. In this case, the far point is given as 80 cm in front of the eye.
3. Corrective Lens:
To correct myopia, a diverging lens is used. A diverging lens is thinner in the center and thicker at the edges. It disperses light rays and causes them to diverge, which helps move the image back to the retina.
4. Lens Power:
The power of a lens is measured in diopters (D). It indicates the ability of the lens to converge or diverge light. A positive power indicates a converging lens, and a negative power indicates a diverging lens.
5. Determining the Lens Power:
To determine the lens power required to correct myopia, we use the formula:
Lens Power (P) = 1 / Focal Length (f)
The focal length is the distance from the lens to the point where parallel light rays converge or diverge.
In this case, the far point is 80 cm in front of the eye. Since the far point is before the retina, a diverging lens is required to move it back to the retina. So, the lens power should be negative.
Using the formula, we calculate:
P = 1 / (-0.8) = -1.25 D
Therefore, the nature and power of the lens required to correct the myopic person's far point of 80 cm in front of the eye is a diverging lens of power -1.25 D.
Hence, the correct answer is option C - a diverging lens of power -1.25 D.
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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer?
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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer?.
The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?a)diverging lens of power +1.25 Db)converging lens of power +1.25 Dc)diverging lens of power -1.25 Dd)converging lens of power -1.25 DCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 10.
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