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[10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.?
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[10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One ...
Calculation of Temperature of Re-radiative Surfaces and Net Radiative Heat Transfer
Temperature of Re-radiative Surfaces:
- The net radiative heat transfer between the two active surfaces can be calculated using the Stefan-Boltzmann law.
- Let's denote the temperatures of the re-radiative surfaces as T1 and T2.
- The net radiative heat transfer between the two active surfaces is given by:
Q = σA(T1^4 - T2^4)
- Given that the black surface at 475 K radiates heat to the other black surface at 375 K, we have:
Q = Aεσ(475^4 - 375^4)
- The net radiative heat transfer Q can also be expressed as the sum of the radiative heat transfer from the 475 K surface to the re-radiative surfaces and from the re-radiative surfaces to the 375 K surface.
Solving for T1 and T2:
- By considering the radiative heat transfer from the 475 K surface to T1 and from T2 to the 375 K surface, we can write:
Q = Aεσ(475^4 - T1^4) + Aεσ(T2^4 - 375^4)
- Equating the two expressions for Q and solving for T1 and T2 gives the temperatures of the re-radiative surfaces.
Thermal Circuit for Radiative Heat Transfer:
- The thermal circuit for radiative heat transfer between the two active surfaces can be represented by a series of resistors representing the thermal resistance of each surface.
- The radiative heat transfer between the two black surfaces can be represented by a resistor with a value corresponding to the net radiative heat transfer.
- The re-radiative surfaces can be represented by resistors with values calculated based on the temperatures of the surfaces.
- The overall thermal circuit can be solved to find the temperatures of the re-radiative surfaces and the net radiative heat transfer between the two active surfaces.
Temperature of Re-radiative Surfaces:
- The net radiative heat transfer between the two active surfaces can be calculated using the Stefan-Boltzmann law.
- Let's denote the temperatures of the re-radiative surfaces as T1 and T2.
- The net radiative heat transfer between the two active surfaces is given by:
Q = σA(T1^4 - T2^4)
- Given that the black surface at 475 K radiates heat to the other black surface at 375 K, we have:
Q = Aεσ(475^4 - 375^4)
- The net radiative heat transfer Q can also be expressed as the sum of the radiative heat transfer from the 475 K surface to the re-radiative surfaces and from the re-radiative surfaces to the 375 K surface.
Solving for T1 and T2:
- By considering the radiative heat transfer from the 475 K surface to T1 and from T2 to the 375 K surface, we can write:
Q = Aεσ(475^4 - T1^4) + Aεσ(T2^4 - 375^4)
- Equating the two expressions for Q and solving for T1 and T2 gives the temperatures of the re-radiative surfaces.
Thermal Circuit for Radiative Heat Transfer:
- The thermal circuit for radiative heat transfer between the two active surfaces can be represented by a series of resistors representing the thermal resistance of each surface.
- The radiative heat transfer between the two black surfaces can be represented by a resistor with a value corresponding to the net radiative heat transfer.
- The re-radiative surfaces can be represented by resistors with values calculated based on the temperatures of the surfaces.
- The overall thermal circuit can be solved to find the temperatures of the re-radiative surfaces and the net radiative heat transfer between the two active surfaces.
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[10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.?
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[10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about [10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for [10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.?.
[10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about [10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for [10] Q-5 1m * 2m * 4m enclosure consists of a rectangle surfaces. One surface of 1m * 2m act as a black surface at 475 K and the other surface of 1m * 2m act as a black surface at 375 K. If the other four surfaces of the enclosure act as re-radiative surfaces, find the temperature of the re- radiative surfaces and the net radiative heat transfer between the two active surfaces. Draw thermal circuit for radiative heat transfer between active surfaces.?.
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