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A beaker containing a liquid of density (ρ) moves up with an acceleration (a). The pressure due to liquid at a depth (h) below the surface of the liquid is
- a)h ρ g
- b)2h ρ g
- c)hρ(g + a)
- d)hρ(g - a)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A beaker containing a liquid of density (ρ) moves up with an accelerat...
As the beaker is moving up with acceleration, so we have to consider pseudo force on the pressure element.
Or simply in P = hpg , (p = density of liquid)
g will change to its apparent value g' = (g+a)
So, pressure at depth h will be, P= h p (g+a)
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A beaker containing a liquid of density (ρ) moves up with an accelerat...
Pressure due to liquid at a depth below the surface:
Explanation:
When a beaker containing a liquid of density (ρ) moves up with an acceleration (a), the pressure due to the liquid at a depth (h) below the surface can be calculated using the following steps:
1. Determine the forces acting on the liquid:
- The weight of the liquid column above the given depth (h) exerts a downward force.
- The buoyant force acting on the liquid exerts an upward force.
- The net force acting on the liquid is the difference between these two forces.
2. Calculate the weight of the liquid column:
- The weight of the liquid column is given by the formula: weight = density × volume × acceleration due to gravity (ρ × A × h × g), where A is the cross-sectional area of the beaker.
3. Calculate the buoyant force:
- The buoyant force is given by the formula: buoyant force = density of liquid × volume of liquid displaced × acceleration due to gravity (ρ × A × h × g).
- The volume of liquid displaced is equal to the volume of the beaker, as the beaker is completely filled with liquid.
4. Calculate the net force:
- The net force acting on the liquid is the difference between the weight of the liquid column and the buoyant force.
- Net force = weight - buoyant force = ρ × A × h × g - ρ × A × h × g = 0.
5. Determine the pressure due to the liquid:
- The pressure due to the liquid at a given depth (h) below the surface is given by the formula: pressure = force / area.
- As the net force is zero, the pressure due to the liquid is also zero.
Therefore, the correct answer is option 'C': hρ(g - a). The pressure due to the liquid at a depth (h) below the surface is hρ(g - a).
Explanation:
When a beaker containing a liquid of density (ρ) moves up with an acceleration (a), the pressure due to the liquid at a depth (h) below the surface can be calculated using the following steps:
1. Determine the forces acting on the liquid:
- The weight of the liquid column above the given depth (h) exerts a downward force.
- The buoyant force acting on the liquid exerts an upward force.
- The net force acting on the liquid is the difference between these two forces.
2. Calculate the weight of the liquid column:
- The weight of the liquid column is given by the formula: weight = density × volume × acceleration due to gravity (ρ × A × h × g), where A is the cross-sectional area of the beaker.
3. Calculate the buoyant force:
- The buoyant force is given by the formula: buoyant force = density of liquid × volume of liquid displaced × acceleration due to gravity (ρ × A × h × g).
- The volume of liquid displaced is equal to the volume of the beaker, as the beaker is completely filled with liquid.
4. Calculate the net force:
- The net force acting on the liquid is the difference between the weight of the liquid column and the buoyant force.
- Net force = weight - buoyant force = ρ × A × h × g - ρ × A × h × g = 0.
5. Determine the pressure due to the liquid:
- The pressure due to the liquid at a given depth (h) below the surface is given by the formula: pressure = force / area.
- As the net force is zero, the pressure due to the liquid is also zero.
Therefore, the correct answer is option 'C': hρ(g - a). The pressure due to the liquid at a depth (h) below the surface is hρ(g - a).
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A beaker containing a liquid of density (ρ) moves up with an acceleration (a). The pressure due to liquid at a depth (h) below the surface of the liquid isa)h ρ gb)2h ρ gc)hρ(g + a)d)hρ(g - a)Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A beaker containing a liquid of density (ρ) moves up with an acceleration (a). The pressure due to liquid at a depth (h) below the surface of the liquid isa)h ρ gb)2h ρ gc)hρ(g + a)d)hρ(g - a)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beaker containing a liquid of density (ρ) moves up with an acceleration (a). The pressure due to liquid at a depth (h) below the surface of the liquid isa)h ρ gb)2h ρ gc)hρ(g + a)d)hρ(g - a)Correct answer is option 'C'. Can you explain this answer?.
A beaker containing a liquid of density (ρ) moves up with an acceleration (a). The pressure due to liquid at a depth (h) below the surface of the liquid isa)h ρ gb)2h ρ gc)hρ(g + a)d)hρ(g - a)Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A beaker containing a liquid of density (ρ) moves up with an acceleration (a). The pressure due to liquid at a depth (h) below the surface of the liquid isa)h ρ gb)2h ρ gc)hρ(g + a)d)hρ(g - a)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A beaker containing a liquid of density (ρ) moves up with an acceleration (a). The pressure due to liquid at a depth (h) below the surface of the liquid isa)h ρ gb)2h ρ gc)hρ(g + a)d)hρ(g - a)Correct answer is option 'C'. Can you explain this answer?.
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