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Consider R² with the usual topology and A,B subset or equal R² then check weather int(A union B)=int(A) union int(B) or not?
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Consider R² with the usual topology and A,B subset or equal R² then ch...




Answer:

Intuition:
The interior of a set consists of all points that are contained within the set without touching the boundary. When we take the union of two sets, the interior of the union may not necessarily be the union of the interiors of the individual sets.

Counterexample:
Let's consider a counterexample to show that int(A ∪ B) ≠ int(A) ∪ int(B).
- Let A = {(x, y) ∈ R² : x² + y² < 1}="" be="" the="" open="" unit="" disk="" centered="" at="" the="" origin.="" -="" let="" b="{(x," y)="" ∈="" r²="" :="" (x-2)²="" +="" y²="" />< 1}="" be="" the="" open="" unit="" disk="" centered="" at="" (2,="" 0).="" then,="" int(a)="A" and="" int(b)="B." however,="" int(a="" ∪="" b)="" contains="" points="" both="" inside="" the="" disk="" centered="" at="" the="" origin="" and="" inside="" the="" disk="" centered="" at="" (2,="" 0),="" which="" is="" not="" equal="" to="" the="" union="" of="" int(a)="" and="" int(b).="" therefore,="" int(a="" ∪="" b)="" ≠="" int(a)="" ∪="" int(b)="" in="" general.="" />
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Consider R² with the usual topology and A,B subset or equal R² then check weather int(A union B)=int(A) union int(B) or not?
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