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 The average weight of 39 Students in a class is 23. Among them Sita is the heaviest while Tina is the lightest. If both of them are excluded from the class still the average remains same. The ratio of weight of Sita to Tina is 15:8.Then what is the weight of the Tina?
  • a)
    15
  • b)
    16
  • c)
    18
  • d)
    19
  • e)
    Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The average weight of 39 Students in a class is 23. Among them Sita is...
S+T = 23*(39-37) = 46
S/T = 15/8
T = 16
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Most Upvoted Answer
The average weight of 39 Students in a class is 23. Among them Sita is...
Given information:
- Average weight of 39 students = 23
- Sita is the heaviest and Tina is the lightest
- Excluding both of them, the average remains the same
- Ratio of Sita's weight to Tina's weight = 15:8

To find: Tina's weight

Solution:

Let the sum of weights of all students excluding Sita and Tina be x.

So, the sum of weights of all 39 students = x + weight of Sita + weight of Tina

Since the average weight is 23, we can write:

(x + weight of Sita + weight of Tina) / 39 = 23

=> x + weight of Sita + weight of Tina = 897 (eq.1)

Also, we know that excluding Sita and Tina, the average weight remains the same. So,

x / 37 = 23

=> x = 851 (eq.2)

Substituting eq.2 in eq.1, we get:

weight of Sita + weight of Tina = 46

Given, the ratio of weight of Sita to Tina is 15:8.

So, let the weight of Tina be 8x. Then, the weight of Sita will be 15x.

From the above equation, we have:

15x + 8x = 46

=> 23x = 46

=> x = 2

Therefore, Tina's weight = 8x = 16.

Hence, the correct option is B.
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The average weight of 39 Students in a class is 23. Among them Sita is the heaviest while Tina is the lightest. If both of them are excluded from the class still the average remains same. The ratio of weight of Sita to Tina is 15:8.Then what is the weight of the Tina?a)15b)16c)18d)19e)Cannot be determinedCorrect answer is option 'B'. Can you explain this answer?
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