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Ranjan’s age is 1/3 of his father’s age.  After 10 years, his father’s age will be twice Raju’s age. If Raju’s eighth birthday was celebrated two years before, then Ranjan’s present age is.
  • a)
    15 yrs.
  • b)
    10 yrs.
  • c)
    12 yrs.
  • d)
    13yrs.
  • e)
    None
Correct answer is option 'B'. Can you explain this answer?
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Ranjan’s age is 1/3 of his father’s age. After 10 years, h...
Now Raju's age = 8+2=10 after 10 years Raju's age =20 father's age=40 now father's age =40-10 =30 Ranjan's age = 30/3 =10
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Ranjan’s age is 1/3 of his father’s age. After 10 years, h...
Given:
- Ranjan's age is 1/3 of his father's age.
- After 10 years, his father's age will be twice Raju's age.
- Raju's eighth birthday was celebrated two years before.

To find: Ranjan's present age.

Solution:
Let's assume Raju's present age is x. Then, his eighth birthday was celebrated 2 years ago, so his age at that time was 8-2=6 years.
So, his present age is x+2 years.

Now, according to the first given condition:
Ranjan's age = 1/3 * Father's age
Let's assume Father's age is y, then:
Ranjan's age = y/3

After 10 years, Father's age will be (y+10) years and Raju's age will be (x+2+10) years = (x+12) years.
According to the second given condition:
Father's age after 10 years = 2 * Raju's age after 10 years
(y+10) = 2(x+12)
y+10 = 2x+24
y = 2x+14

Now, we can substitute y = 2x+14 in the equation for Ranjan's age:
Ranjan's age = y/3 = (2x+14)/3

We know that Ranjan's age + Raju's age = Father's age
So, (2x+14)/3 + (x+2) = y
(2x+14)/3 + (x+2) = 2x+14
3x+6 = 6x+42
3x = 36
x = 12

Therefore, Raju's present age is x+2 = 14 years.
And Ranjan's present age is y/3 = (2x+14)/3 = (2*12+14)/3 = 10 years.

Hence, option B is the correct answer.
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Ranjan’s age is 1/3 of his father’s age. After 10 years, his father’s age will be twice Raju’s age. If Raju’s eighth birthday was celebrated two years before, then Ranjan’s present age is.a)15 yrs.b)10 yrs.c)12 yrs.d)13yrs.e)NoneCorrect answer is option 'B'. Can you explain this answer?
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