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A ray of light enters a glass slab at an angle of incidence equal to 30 degree and travel inside the glass slab at an angle of 20 degree. Find the refractive index..(Given that Sin 20 degree = 1/3,Sin 30 degree = 1/2?
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Calculating the Refractive Index of the Glass Slab
To find the refractive index of the glass slab, we can use Snell's Law which states:
\[ \frac{\sin{i}}{\sin{r}} = \frac{n_2}{n_1} \]
where
- \( i \) is the angle of incidence
- \( r \) is the angle of refraction
- \( n_1 \) is the refractive index of the medium from which the light is coming
- \( n_2 \) is the refractive index of the medium into which the light is entering

Given Data:
- Angle of incidence, \( i = 30^\circ \)
- Angle of refraction, \( r = 20^\circ \)
- \( \sin{20^\circ} = \frac{1}{3} \)
- \( \sin{30^\circ} = \frac{1}{2} \)

Calculations:
\[ \frac{\sin{30^\circ}}{\sin{20^\circ}} = \frac{n_{\text{glass}}}{1} \]
\[ \frac{\frac{1}{2}}{\frac{1}{3}} = \frac{n_{\text{glass}}}{1} \]
\[ \frac{3}{2} = n_{\text{glass}} \]
Therefore, the refractive index of the glass slab is 1.5.
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A ray of light enters a glass slab at an angle of incidence equal to 30 degree and travel inside the glass slab at an angle of 20 degree. Find the refractive index..(Given that Sin 20 degree = 1/3,Sin 30 degree = 1/2?
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