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A ray of light traveling in air falls on the surface of a transparent glass slab at an angle of 60º with the normal to the surface. Find the angle made by the refracted ray with the normal within the glass slab. Refractive index of the material of the glass slab is 1.5
- a)30º
- b)25º
- c)35º
- d)60º
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A ray of light traveling in air falls on the surface of a transparent ...
We know that refractive index of glass slab is 1.5
Here the incidence angle is i=60o
Using snell's law
nairsin(i) = nglasssin(r)
sin60o = 1.5sinr
=> √3/2 = 1.5sinr
=> 1/√3 = sin r
=> r = 35.26o ≈ 35o
Most Upvoted Answer
A ray of light traveling in air falls on the surface of a transparent ...
Using formula sin i equal n then 1by 3 is the value of sinr 35.26degree
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A ray of light traveling in air falls on the surface of a transparent ...
The ray of light entering the transparent glass slab will refract, or bend, according to Snell's Law. The angle of refraction can be calculated using the formula:
n₁sinθ₁ = n₂sinθ₂
Where:
n₁ = refractive index of air
θ₁ = angle of incidence in air
n₂ = refractive index of glass
θ₂ = angle of refraction in glass
Assuming the refractive index of air is approximately 1, and the refractive index of the glass slab is 1.5, we can substitute these values into the formula:
1 * sin(60) = 1.5 * sin(θ₂)
Rearranging the equation to solve for θ₂, we get:
sin(θ₂) = (1 * sin(60)) / 1.5
sin(θ₂) = sin(60) / 1.5
Using a calculator, we find:
sin(θ₂) ≈ 0.866 / 1.5
θ₂ ≈ sin^(-1)(0.577)
The angle of refraction in the glass slab is approximately 35.26 degrees.
n₁sinθ₁ = n₂sinθ₂
Where:
n₁ = refractive index of air
θ₁ = angle of incidence in air
n₂ = refractive index of glass
θ₂ = angle of refraction in glass
Assuming the refractive index of air is approximately 1, and the refractive index of the glass slab is 1.5, we can substitute these values into the formula:
1 * sin(60) = 1.5 * sin(θ₂)
Rearranging the equation to solve for θ₂, we get:
sin(θ₂) = (1 * sin(60)) / 1.5
sin(θ₂) = sin(60) / 1.5
Using a calculator, we find:
sin(θ₂) ≈ 0.866 / 1.5
θ₂ ≈ sin^(-1)(0.577)
The angle of refraction in the glass slab is approximately 35.26 degrees.
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A ray of light traveling in air falls on the surface of a transparent glass slab at an angle of 60º with the normal to the surface. Find the angle made by the refracted ray with the normal within the glass slab. Refractive index of the material of the glass slab is 1.5a)30ºb)25ºc)35ºd)60ºCorrect answer is option 'C'. Can you explain this answer?
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A ray of light traveling in air falls on the surface of a transparent glass slab at an angle of 60º with the normal to the surface. Find the angle made by the refracted ray with the normal within the glass slab. Refractive index of the material of the glass slab is 1.5a)30ºb)25ºc)35ºd)60ºCorrect answer is option 'C'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A ray of light traveling in air falls on the surface of a transparent glass slab at an angle of 60º with the normal to the surface. Find the angle made by the refracted ray with the normal within the glass slab. Refractive index of the material of the glass slab is 1.5a)30ºb)25ºc)35ºd)60ºCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ray of light traveling in air falls on the surface of a transparent glass slab at an angle of 60º with the normal to the surface. Find the angle made by the refracted ray with the normal within the glass slab. Refractive index of the material of the glass slab is 1.5a)30ºb)25ºc)35ºd)60ºCorrect answer is option 'C'. Can you explain this answer?.
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