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The sum of the numerator and denominator of fraction is 4 more than twice of the numerator if the demorator and numerator increased by 3 they are in the ratio 2:3 determine the fraction?
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The sum of the numerator and denominator of fraction is 4 more than tw...



Given Information:
- Sum of numerator and denominator = 2n + d = 2n + 4
- After increasing numerator and denominator by 3, ratio becomes 2:3

Let's solve the problem step by step:



Step 1: Set up the equations
- From the given information, we have:
1. 2n + d = 2n + 4
2. (n + 3)/(d + 3) = 2/3

Step 2: Solve the first equation
- Simplifying equation 1, we get:
d = 4

Step 3: Solve the second equation
- Substituting d = 4 in equation 2, we get:
(n + 3)/(4 + 3) = 2/3
(n + 3)/7 = 2/3
3(n + 3) = 14
3n + 9 = 14
3n = 5
n = 5/3

Step 4: Determine the fraction
- The fraction is n/d = 5/4

Final Answer:
- The fraction is 5/4

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The sum of the numerator and denominator of fraction is 4 more than twice of the numerator if the demorator and numerator increased by 3 they are in the ratio 2:3 determine the fraction?
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