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Solution of a quadratic equation x²+ 5x - 6 = 0
  • a)
    x = -1, x = 6
  • b)
    x = 1, x = - 6
  • c)
    x = 1
  • d)
    x = 6
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Solution of a quadratic equation x²+ 5x - 6 = 0a)x = -1, x = 6b)x...
x^2 + 5x - 6 = 0
is factored into this:
(x + 6) * (x - 1) = 0

x * (x - 1) + 6 * (x - 1) = 0
x^2 - x + 6x - 6 = 0
x^2 + 5x - 6 = 0

In its factored form, it is easy to see that if either term inside the parentheses can be set to zero, then no matter what it is multiplied by, the equation still results in zero.

If we set x = -6, or 1, then the equation is satisfied. You should go back into the original equation and check your work.
...
x = -6:
-6^2 + 5(-6) - 6 = 0
36 - 30 - 6 = 0
0 = 0 checks
...
x = 1:
1^2 + 5(1) - 6 = 0
1 + 5 - 6 = 0
0 = 0 checks
...
Solutions are x = -6, 1
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Most Upvoted Answer
Solution of a quadratic equation x²+ 5x - 6 = 0a)x = -1, x = 6b)x...
The expression "anxn" represents the term in a polynomial where "a" is the coefficient and "n" is the exponent of the variable "x".

If n is a non-negative integer, it means that n can be 0, 1, 2, 3, and so on.

For example, if n = 0, then the term would be a0x0, which simplifies to just "a0".

If n = 1, then the term would be a1x1, which simplifies to "a1x".

If n = 2, then the term would be a2x2.

And so on. The value of "n" determines the exponent of "x" in the term.
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Community Answer
Solution of a quadratic equation x²+ 5x - 6 = 0a)x = -1, x = 6b)x...
The correct one here is B as when we use the quadratic formula which is -b+-√b²-4ac/wa
it gives us -5+-√5²-4(1)(-6)/2(1)
-5+-√25+24/2
-5+-√49/2
-5+-7/2
for -5+7/2
2/2
1
and for -5-7/2
-12/2
-6
so x can be either 1 or -6
hope it helps!!
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Solution of a quadratic equation x²+ 5x - 6 = 0a)x = -1, x = 6b)x = 1, x = - 6c)x = 1d)x = 6Correct answer is option 'B'. Can you explain this answer?
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