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4x² + 8x + 3 = 0
4y² – 29y + 45 = 0
  • a)
    X > Y
  • b)
    X < Y
  • c)
    X ≥ Y
  • d)
    X ≤ Y
  • e)
    X = Y or relation cannot be established
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
4x² + 8x + 3 = 04y² – 29y + 45 = 0a)X > Yb)X < Y...
4x² + 8x + 3 = 0
x = -0.5, -3.5
4y² – 29y + 45 = 0
y = 2.25, 5
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Most Upvoted Answer
4x² + 8x + 3 = 04y² – 29y + 45 = 0a)X > Yb)X < Y...
4x² + 8x + 3 = 0
x = -0.5, -3.5
4y² – 29y + 45 = 0
y = 2.25, 5
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4x² + 8x + 3 = 04y² – 29y + 45 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer?
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