Class 10 Exam > Class 10 Questions > Give equation. Px + qy = p-q/qx-py=p+q, find ...
Start Learning for Free
Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ?
Most Upvoted Answer
Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ?
Equation: Px qy = p-q/qx-py=p q
Finding x and y by substitution:
1. Rearrange the second part of the equation to solve for one variable. Let's solve for x:
- pxqy - p + q = -qxpy + pqx
- p(xq + q) = q(xp - 1)
- x = (q-p)/(pq-qy)
2. Substitute the value of x into one of the equations to solve for y. Let's use the first equation:
- Px qy = p - q/(q-p)y = p/q - y
- qy - py = pq/q - py/q - yq
- y(q-p) = pq/q - p/q
- y = p/(q-p)
3. Check the solution by substituting x and y into both equations:
- Px qy = P(q-p)/(pq-qy) * q * p/(q-p) = p
- p-q/qx-py = p-q/(q-p)*(q-p)/(pq-qy)*q/(q-p) = q
Therefore, the solution to the equation is x = (q-p)/(pq-qy) and y = p/(q-p).
Finding x and y by substitution:
1. Rearrange the second part of the equation to solve for one variable. Let's solve for x:
- pxqy - p + q = -qxpy + pqx
- p(xq + q) = q(xp - 1)
- x = (q-p)/(pq-qy)
2. Substitute the value of x into one of the equations to solve for y. Let's use the first equation:
- Px qy = p - q/(q-p)y = p/q - y
- qy - py = pq/q - py/q - yq
- y(q-p) = pq/q - p/q
- y = p/(q-p)
3. Check the solution by substituting x and y into both equations:
- Px qy = P(q-p)/(pq-qy) * q * p/(q-p) = p
- p-q/qx-py = p-q/(q-p)*(q-p)/(pq-qy)*q/(q-p) = q
Therefore, the solution to the equation is x = (q-p)/(pq-qy) and y = p/(q-p).
Community Answer
Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ?
|
Explore Courses for Class 10 exam
|
|
Similar Class 10 Doubts
Top Courses for Class 10View all
Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ?
Question Description
Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ?.
Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ?.
Solutions for Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? in English & in Hindi are available as part of our courses for Class 10.
Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Here you can find the meaning of Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? defined & explained in the simplest way possible. Besides giving the explanation of
Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ?, a detailed solution for Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? has been provided alongside types of Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? theory, EduRev gives you an
ample number of questions to practice Give equation. Px + qy = p-q/qx-py=p+q, find and by substitution. ? tests, examples and also practice Class 10 tests.
|
|
Explore Courses for Class 10 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup