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If alpha and beeta are the zeroes of x2+x-2, then find aphabeeta2 + alpha2beeta?
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If alpha and beeta are the zeroes of x2+x-2, then find aphabeeta2 + al...
Given Information:
- Zeroes of the quadratic equation x^2 + x - 2 are alpha and beta.

Formula:
- Sum of zeroes (alpha + beta) = -b/a
- Product of zeroes (alpha * beta) = c/a

Calculation:
- In this case, a = 1, b = 1, and c = -2 from the given quadratic equation x^2 + x - 2.

Finding the Sum and Product of Zeroes:
- Sum of zeroes (alpha + beta) = -b/a = -1/1 = -1
- Product of zeroes (alpha * beta) = c/a = -2/1 = -2

Finding the Required Expression:
- We need to find alpha^2 * beta + alpha * beta^2.
- By expanding this expression, we get alpha^2 * beta + alpha * beta^2 = alpha * beta * (alpha + beta).
- Substituting the values of alpha + beta and alpha * beta, we get alpha^2 * beta + alpha * beta^2 = -2 * -1 = 2.

Final Answer:
- Therefore, aphabeeta^2 + alpha^2beeta = 2.
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If alpha and beeta are the zeroes of x2+x-2, then find aphabeeta2 + alpha2beeta?
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