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40. sin the wave function of a particle of m mans in one dimension, where p and E are the momentum and energy of the particle which of the following cannot be an outcome of a measurement? respectively. Ther v = (1 ^ 2 * x) * dy (q/(sy)) * dxg(q/(dz)) (a) The momentum of the particle is p (b) Energy of the particle is p2m (c) Momentum is-p (d) Momentum is zero Operatin?
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40. sin the wave function of a particle of m mans in one dimension, wh...
Cannot be an Outcome of Measurement in Wave Function

The Momentum of the Particle is p:
- This can be an outcome of a measurement since momentum is a physical quantity that can be measured.

Energy of the Particle is p^2m:
- This cannot be an outcome of a measurement as the energy of a particle is given by E = p^2 / (2m) in one dimension, not p^2m.

Momentum is -p:
- This can be an outcome of a measurement as momentum can have both positive and negative values.

Momentum is Zero:
- This can be an outcome of a measurement, where the particle is at rest and has zero momentum.
In summary, the energy of the particle being p^2m cannot be an outcome of a measurement in the wave function of a particle of mass m in one dimension, as it does not correspond to the correct formula for energy in such a system.
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Passage 2Newtons surprising success at developing the laws of motion, as well as the development and refinement of other physical laws, led to the idea of scientific determinism. The first expression of this principle was in the beginning of the nineteenth century by Laplace, a French scientist. Laplace argued that if one knew the position and velocity of all the particles in the universe at a given time, the laws of physics would be able to predict the future state ofthe universe.Scientific determinism held sway over a great many scientists until the early twentieth century, when the quantum mechanics revolution occurred. Quantum mechanics introduced the world to the idea of the uncertainty principle, which stated that it was impossible to accurately measure both the position and the velocity of a particle at one time. Because Laplaces omniscience could never occur, even in theory, the principle of scientific determinism was thrown into doubt. However, quantum mechanics does allow for a reduced form of scientific determinism. Even though physicists are unable to know precisely where a particle is and what its velocity is, they can determine certain probabilities about its position and velocity. These probabilities are called wave functions. By use of a formula known as the Schrodinger equation, a scientist with the wave function of a particle at a given time can calculate the particles future wave function. These calculations can give the particles position or velocity, but not both. Thus, the physicist is in possession of exactly half ofthe information needed to satisfy Laplaces view ofdeterminism. Unfortunately, under modern physics theories, that is far as any researcher can go in predicting the future.Q. The passage suggests that if scientific determinism were true

Passage 2Newtons surprising success at developing the laws of motion, as well as the development and refinement of other physical laws, led to the idea of scientific determinism. The first expression of this principle was in the beginning of the nineteenth century by Laplace, a French scientist. Laplace argued that if one knew the position and velocity of all the particles in the universe at a given time, the laws of physics would be able to predict the future state ofthe universe.Scientific determinism held sway over a great many scientists until the early twentieth century, when the quantum mechanics revolution occurred. Quantum mechanics introduced the world to the idea of the uncertainty principle, which stated that it was impossible to accurately measure both the position and the velocity of a particle at one time. Because Laplaces omniscience could never occur, even in theory, the principle of scientific determinism was thrown into doubt. However, quantum mechanics does allow for a reduced form of scientific determinism. Even though physicists are unable to know precisely where a particle is and what its velocity is, they can determine certain probabilities about its position and velocity. These probabilities are called wave functions. By use of a formula known as the Schrodinger equation, a scientist with the wave function of a particle at a given time can calculate the particles future wave function. These calculations can give the particles position or velocity, but not both. Thus, the physicist is in possession of exactly half ofthe information needed to satisfy Laplaces view ofdeterminism. Unfortunately, under modern physics theories, that is far as any researcher can go in predicting the future.Q. According to the passage, wave functions

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40. sin the wave function of a particle of m mans in one dimension, where p and E are the momentum and energy of the particle which of the following cannot be an outcome of a measurement? respectively. Ther v = (1 ^ 2 * x) * dy (q/(sy)) * dxg(q/(dz)) (a) The momentum of the particle is p (b) Energy of the particle is p2m (c) Momentum is-p (d) Momentum is zero Operatin?
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40. sin the wave function of a particle of m mans in one dimension, where p and E are the momentum and energy of the particle which of the following cannot be an outcome of a measurement? respectively. Ther v = (1 ^ 2 * x) * dy (q/(sy)) * dxg(q/(dz)) (a) The momentum of the particle is p (b) Energy of the particle is p2m (c) Momentum is-p (d) Momentum is zero Operatin? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 40. sin the wave function of a particle of m mans in one dimension, where p and E are the momentum and energy of the particle which of the following cannot be an outcome of a measurement? respectively. Ther v = (1 ^ 2 * x) * dy (q/(sy)) * dxg(q/(dz)) (a) The momentum of the particle is p (b) Energy of the particle is p2m (c) Momentum is-p (d) Momentum is zero Operatin? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 40. sin the wave function of a particle of m mans in one dimension, where p and E are the momentum and energy of the particle which of the following cannot be an outcome of a measurement? respectively. Ther v = (1 ^ 2 * x) * dy (q/(sy)) * dxg(q/(dz)) (a) The momentum of the particle is p (b) Energy of the particle is p2m (c) Momentum is-p (d) Momentum is zero Operatin?.
Solutions for 40. sin the wave function of a particle of m mans in one dimension, where p and E are the momentum and energy of the particle which of the following cannot be an outcome of a measurement? respectively. Ther v = (1 ^ 2 * x) * dy (q/(sy)) * dxg(q/(dz)) (a) The momentum of the particle is p (b) Energy of the particle is p2m (c) Momentum is-p (d) Momentum is zero Operatin? in English & in Hindi are available as part of our courses for UPSC. Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
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