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2(ax-by)+(a+4b)=0 2(bx+ay)+(b-4a)=0 solve for x n y?
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2(ax-by)+(a+4b)=0 2(bx+ay)+(b-4a)=0 solve for x n y?
Solving the Equations for x and y:
- Step 1: Simplify the Equations
Given equations are:
1. 2(ax - by) + (a + 4b) = 0
2. 2(bx + ay) + (b - 4a) = 0
Let's simplify these equations:
1. 2ax - 2by + a + 4b = 0
2. 2bx + 2ay + b - 4a = 0
- Step 2: Rearrange the Equations
Rearranging the equations in terms of x and y:
1. 2ax + a = 2by - 4b
2. 2ay - 4a = -2bx - b
- Step 3: Solve for x and y
From equation 1:
x = (2by - 4b - a) / 2a
x = (b(2y - 4) - a) / 2a
x = (b(2y - 4) - a) / 2a
Substituting x into equation 2:
2ay - 4a = -2b((b(2y - 4) - a) / 2a) - b
2ay - 4a = -b(2y - 4) + a
2ay - 4a = -2by + 4b + a
2ay + 2by = 4a + 4b
y(2a + 2b) = 4(a + b)
y = 4(a + b) / 2(a + b)
y = 2
Therefore, the solutions for x and y are:
x = (b(2y - 4) - a) / 2a
y = 2
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2(ax-by)+(a+4b)=0 2(bx+ay)+(b-4a)=0 solve for x n y?
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