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Gautam and Suhani, working together, can finish a job in 20 days. If Gautam does only 60% of his usual work on a day, Suhani must do 150% of her usual work on that day to exactly make up for it. Then, the number of days required by the faster worker to complete the job working alone is
[2023]
Correct answer is '36'. Can you explain this answer?
Most Upvoted Answer
Gautam and Suhani, working together, can finish a job in 20 days. If G...
If Gautam does only 60% of his usual work on a day, Suhani must do 150% of her usual work on that day to exactly make up for it.
This means 40% of Gautam's work in a day = 50% of Suhani's work in a day 40% of Gautam's capacity' = 50% of Suhani's capacity Gautam is 1.25 as efficient as Suhani.
Let us say Suhani can finish the 1 piece of work in x days. Then, Gautam can finish 1.25 pieces of work in x days.
So, if they work together, they for x days, they can finish 2.25 pieces of work.
So, to finish one piece of work they need x/2.25 days.
x/2.25 = 20
x = 45 days.
Since Gautam is 1.25 times faster than Sahani, he takes 45/1.25 = 36 days.
So, the faster one takes 36 days to finish the job.
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Community Answer
Gautam and Suhani, working together, can finish a job in 20 days. If G...
Given Information:
- Gautam and Suhani can finish a job together in 20 days.
- If Gautam does 60% of his usual work, Suhani must do 150% of her usual work to make up for it.
- We need to find the number of days required by the faster worker to complete the job alone.

Calculating Individual Efficiency:
Let's assume Gautam's usual work in a day is G and Suhani's usual work in a day is S.
Given, G + S = 1/20 (as they complete the job in 20 days)
When Gautam does 60% of his work, he does 0.6G work in a day.
To make up for it, Suhani must do 150% of her work, which is 1.5S.
So, 0.6G + 1.5S = 1/20
Solving these two equations, we get G = 1/30 and S = 1/60

Calculating Individual Time:
Now, we need to find the number of days required by the faster worker to complete the job alone.
Let's assume the faster worker is Gautam.
Gautam can complete the job alone in 1/G days = 30 days.
Therefore, the number of days required by the faster worker (Gautam) to complete the job working alone is 30 days.
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Gautam and Suhani, working together, can finish a job in 20 days. If Gautam does only 60% of his usual work on a day, Suhani must do 150% of her usual work on that day to exactly make up for it. Then, the number of days required by the faster worker to complete the job working alone is[2023]Correct answer is '36'. Can you explain this answer?
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