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An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will be
- a)q/4πε0
- b)2q/4πε0
- c)14q/4πε0
- d)q/3πε0
Correct answer is option 'B'. Can you explain this answer?
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B) q/2c) qd) 2q/3
The electric potential at any point due to a collection of point charges is given by the formula:
V = kΣ(qi/ri)
where k is Coulomb's constant, qi is the magnitude of the ith charge, and ri is the distance from the ith charge to the point where the potential is being calculated.
In this case, we have an infinite number of charges of alternating sign, so we can split the sum into two parts:
V = kΣ(qi/ri) = kΣ(qi/ri) + kΣ(-qi/ri)
The first sum is over all the positive charges, and the second is over all the negative charges. Since the charges are arranged in a geometric series (doubling in magnitude at each step), we can write ri as:
ri = 2^(i-1)
So our formula becomes:
V = kΣ(q/2^(i-1)) - kΣ(q/2^(i-1))
The two sums cancel each other out, leaving us with:
V = 0
So the electric potential at x=0 due to these charges is zero. Answer: 0.
The electric potential at any point due to a collection of point charges is given by the formula:
V = kΣ(qi/ri)
where k is Coulomb's constant, qi is the magnitude of the ith charge, and ri is the distance from the ith charge to the point where the potential is being calculated.
In this case, we have an infinite number of charges of alternating sign, so we can split the sum into two parts:
V = kΣ(qi/ri) = kΣ(qi/ri) + kΣ(-qi/ri)
The first sum is over all the positive charges, and the second is over all the negative charges. Since the charges are arranged in a geometric series (doubling in magnitude at each step), we can write ri as:
ri = 2^(i-1)
So our formula becomes:
V = kΣ(q/2^(i-1)) - kΣ(q/2^(i-1))
The two sums cancel each other out, leaving us with:
V = 0
So the electric potential at x=0 due to these charges is zero. Answer: 0.
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An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will bea)q/4πε0b)2q/4πε0c)14q/4πε0d)q/3πε0Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will bea)q/4πε0b)2q/4πε0c)14q/4πε0d)q/3πε0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will bea)q/4πε0b)2q/4πε0c)14q/4πε0d)q/3πε0Correct answer is option 'B'. Can you explain this answer?.
An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will bea)q/4πε0b)2q/4πε0c)14q/4πε0d)q/3πε0Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will bea)q/4πε0b)2q/4πε0c)14q/4πε0d)q/3πε0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An infinite number of charge of equal magnitude q, but of opposite sign are placed along the X-axis at x = 1, x = 2, x = 4, x = 8... and so on. The electric potential at the point x = 0 due to these charge will bea)q/4πε0b)2q/4πε0c)14q/4πε0d)q/3πε0Correct answer is option 'B'. Can you explain this answer?.
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